Height of the water increasing is at rate of 
<h3>How to solve?</h3>
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

In the problem, we are given
So we need to substitute this in:

Hence, Height of the water increasing is at rate of 
<h3>Formula used: </h3>

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Creo que es A si no es porfavor dime.
85÷17=5
the average change in field position on each run is 5 yards
<u>Answer </u><u>:</u><u>-</u>
Given inequality ,
- -5x +3y > 12
- 3y > 5x + 12
- y > 5/3x + 12/3
- y > 5/3x + 4
From the options ,
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>and </u><u>y </u><u>=</u><u> </u><u>9</u>
- y >1* 5 + 4
- y > 5 +4
- 9> 9 ( Not possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>5</u><u> </u><u>y</u><u> </u><u>is </u><u>5</u><u> </u>
- y > 5/3*-5 + 4
- y > -8.3 + 4
- 5 > -3.7 ( Possible )
<u>When </u><u>x </u><u>is </u><u>3</u><u> </u><u>y </u><u>is </u><u>-</u><u>6</u><u> </u>
- y > 5 + 4
- -6 > 9 ( Not possible )
<u>When </u><u>x </u><u>is </u><u>-</u><u>2</u><u> </u><u>y </u><u>is </u><u>-</u><u>5</u><u> </u>
- y > -3.33 + 4
- -5 > -0.67 ( Possible )
<u>When </u><u>x </u><u>is </u><u>2</u><u> </u><u>y </u><u>is </u><u>8</u><u> </u>
- y > 3.33 + 4
- 8 > 7.77 ( possible )
<u>When</u><u> </u><u>x </u><u>is </u><u>-</u><u>6</u><u> </u><u>y </u><u>is </u><u>0</u><u> </u>
- y > -10 +4
- 0 > -6 ( possible )
By Pythagoras Theorem,
the length of the other leg= (63^2-52^2)^1/2
hope this helps :)