The magnitude of the acceleration of the elevator is 90m/s^2
Due to Newton's Law ∑ Forces in direction of motion is equal to mass
multiplied by the acceleration
We have here two forces 5000 N in direction of motion and the weight of the person in opposite direction of motion
The weight of the person is his mass multiplied by the acceleration of gravity
So ,
W = mg , where m is the mass and g is the acceleration of gravity
m = 50 kg and g = 9.8 m/s²
Substitute these values in the rule above
W = 50 × 9.8 = 490 N
The scale reads 5000 N
F = 5000 N , W = 490 N , m = 50kg
F - W = ma
5000 - 490 = 50 a
4510 = 50 a
Divide both sides by 50
a = 90.2 m/s²
Hence the acceleration is 90m/s^2
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Answer:
Density = 1.1839 kg/m³
Mass = 227.3088 kg
Specific Gravity = 0.00118746 kg/m³
Explanation:
Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³
Now, from tables, density of air at 25°C is 1.1839 kg/m³
Now formula for density is;
ρ = mass(m)/volume(v)
Plugging in the relevant values to give;
1.1839 = m/192
m = 227.3088 kg
Formula for specific gravity of air is;
S.G_air = density of air/density of water
From tables, density of water at 25°C is 997 kg/m³
S.G_air = 1.1839/997 = 0.00118746 kg/m³
The velocity is the integral of acceleration. If acceleration is 100 m/s^2 then velocity is:
So to know the velocity at any time, t, we just put t in seconds into this equation. To know at what time we get to a certain velocity, we set this equation equal to that velocity and solve for t:
When you are going down you pick up more speed
