All categories

3 years ago

Energy is _______ when it's moved from one object to another.

Physics

2 answers:

zzz [600]3 years ago

3 0

Energy is (transferred) when it is moved from one obect to another.

The answer is (b)

Margarita [4]3 years ago

3 0

Energy is transferred when it's moved from one object to another.

That is because energy cannot be created nor destroyed, only conducted. <span />

You might be interested in

What part of the roller coaster has the lowest potential energy?

zubka84 [21]

It’s 1 that would be the lowest point potential energy

6 0

4 years ago

What fraction of Earth’s volume is taken up by the core?

STALIN [3.7K]

Answer:

Although the core and mantle are about equal in thickness, the core actually forms only 15 percent of the Earth's volume, whereas the mantle occupies 84 percent. The crust makes up the remaining 1 percent.

4 0

3 years ago

Which one of the following is the pigment found in redheads?

coldgirl [10]

The pigment found in redheads in pheomelanin

4 0

3 years ago

The index of refraction of a clear plastic is listed as 1.89 in the book, but you measured the angle of incidence 63.5° and the

lakkis [162]

Answer:

<h2>index of refraction = 1.69</h2><h2>percentage error = 10.58%</h2>

Explanation:

According to Snell's law, the ratio of the sine of angle of incidence to the sine of angle of refraction is a constant for a given pair of media. The constant is known as the refractive index.

Mathematically $\frac{sin i}{sin r} = n$

i = angle of incidence measured = 63.5°

r = angle of refraction measured = 32°

n = refractive index

$n = \frac{sin 63.5^{0} }{sin 32^{0} } \\n = \frac{0.8949}{0.5299}\\ n = 1.69$

The index fraction calculated is approx. 1.69.

If the index of refraction of a clear plastic as listed in the book is 1.89 and the calculated is 1.69, the percentage error will be calculated as thus;

%error = $\frac{1.89-1.69}{1.89} * 100$

%error = $\frac{0.2}{1.89}*100$

%error = $\frac{20}{1.89}$

%error = 10.58%

6 0

4 years ago

A car is driven at constant speed over a circular hill and then into a circular valley with the same radius. At the top of the h

VashaNatasha [74]

Answer:

therefore normal reaction on the driver from the seat when the car passes through the bottom of the valley= 1520.55 N

Explanation:

let speed be v

at top of hill

mg-N = mv^2/R ( N=0 at the top of the hill)

==> mg=mv^2/R

at bottom

N-mg=mv^2/R

therefore,

N = 2mg = 2*77.8*9.81= 1520.55 N

therefore normal reaction on the driver from the seat when the car passes through the bottom of the valley= 1520.55 N

7 0

3 years ago