All categories

3 years ago

What best describes the degree to which a material can transmit heat

2 answers:

8 0

BOILING POINT BECAUSE BOILING POINT IS THE POINT AT WHICH A MATERIAL OR SUBSTANCE IS MADE PURE AND FOR A SUBSTANCE TO BE MADE PURE IT NEED TO ABSORB AND GIVE OUT HEAT COS BOILING REACTION IS EXOTHERMIC

kirill115 [55]3 years ago

7 0

The correct answer is C. Thermal conductivity

Explanation:

Conduction occurs as heat, electricity, etc. are transmitted from one body to another. In the case of thermal conductivity, this refers to the property of one material or body to transmit or conduct heat. This property is measured in Watts (energy) per meter(distance)-Kelvin (temperature). For example, the thermal conductivity of copper is around 385 while the one of ice is 1.6, which indicates copper has a higher capability to conduct heat. Thus, the degree to which a material can transmit heat is thermal conductivity.

You might be interested in

Increase the slit width to 1050 nm. What happens to the width of the central bright fringe? (Always remember to wait a few secon

djyliett [7]

Answer:

Explanation:

In case of Single Slit, diffraction will occur.

Then In Single slit Diffraction, width of central fringe is

$x_c= 2D\lambda/a
$

where D= distance b/w screen and slit

a= slit width

\lambda = wavelength

Thus if Screen width increases keeping other factors same then width of central fringe becomes narrower as

$x_c\propto 1/a$

On increasing the slit width the central bright fringe width The width of the central bright fringe becomes narrower.

3 0

3 years ago

A layer of oil (n = 1.38) floats on an unknown liquid. A ray of light originates in the oil and passes into the unknown liquid.

Vinil7 [7]

Answer:

Refractive index of unknown liquid = 1.56

Explanation:

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 65.0° )

${\theta_r}$ is the angle of refraction ( 53.0° )

${n_r}$ is the refractive index of the refraction medium (unknown liquid, n=?)

${n_i}$ is the refractive index of the incidence medium (oil, n=1.38)

Hence,

$1.38\times {sin65.0^0}={n_r}\times{sin53.0^0}$

Solving for ${n_r}$ ,

Refractive index of unknown liquid = 1.56

4 0

3 years ago

Why is it so good for scientists to be skeptical

IceJOKER [234]

Its good for a scientist to be skeptical because they dont willingly accept new ideas without thoroughly going over the research themselves and attempting to disprove a theory. skeptical scientists often reveal new information through doing their own examinations of a concept, which is why they are valuable scientists

7 0

3 years ago

Correct the following statement:

ankoles [38]

Answer:

It's the 3rd option

Explanation:

Wind is caused by the differences in air pressure on Earth's surface.

4 0

3 years ago

A boy throws a ball of mass 0.22 kg straight upward with an initial speed of 29 m/s. When the ball returns to the boy, its speed

maksim [4K]

Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is $\frac{1}{2} *m*(vf^{2} -vi^{2} )$

You know:

mass=m=0.22 kg
Initial velocity of the ball: $vi= 29 \frac{m}{s}$

Final velocity of the ball: $vf= 15 \frac{m}{s}$

Replacing:

$\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )$ = -67.76 J

Friction work is always negative because friction is always against displacement.

5 0

3 years ago