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3 years ago

Select the statement that best describes gravity.

Physics

1 answer:

pav-90 [236]3 years ago

6 0

Explanation:

Gravity is the force of attraction between two objects. It depends upon the mass of the objects and the distance between the objects. Mathematically, the force of gravity is given by :

$F=G\dfrac{m_1m_2}{d^2}$

Where

G is the universal gravitational constant

$m_1\ and\ m_2$ are masses

d is the distance between two masses

So, statement (2) describes gravity "Gravity is the force of attraction between two objects; it is dependent upon the mass of the objects and the distance between the objects".

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under what circumstances can the average velocity of a moving object be zero when its average speed is 50 km/hr ?

german

If the displacement = zero the average velocity will be zero. displacement = zero when the object move and return back to its starting position

5 0

2 years ago

The movement of water between the atmosphere, land, oceans, and even living things makes up the water cycle. Precipitation is on

Anna [14]

I have no idea

Explanation:

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2 years ago

A 1380 kg car starts from rest at the

Ulleksa [173]

Answer: 72200

Explanation:

First you must find the height for this is on an inclined hill using:

h=Lsin(angle) —> 28.0sin(11.0) = 5.34

Now you would just use the PE equation (mgh) because you are finding ME and when you starting from the top KE=0, showing that what ever answer you get from PE would equal the same for ME.

Using mgh:

m=1380

g=9.80

h=5.34

(1380)(9.8)(5.34)

=72218.16

*Rounding to the 3rd=72200

Hope this helps :)

6 0

2 years ago

A particle of mass 10 g and charge 72 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is

sineoko [7]

Answer:

$-0.07163\hat k\ T$ or 0.07163 T into the page

Explanation:

m = Mass of particle = 10 g

a = Acceleration due to gravity = -9.8j m/s²

v = Velocity of particle = 19i km/s

q = Charge of particle = 72 μC

B = Magnetic field

Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,

$F_b=F_g$

$F_b=qvBsin\theta\\\Rightarrow F_b=qvBsin90\\\Rightarrow F_b=72\times 10^{-6}\times 19000B$

$F_g=ma\\\Rightarrow F_g=0.01\times -9.8$

$72\times 10^{-6}\times 19000B=0.01\times -9.8\\\Rightarrow B=\frac{0.01\times -9.8}{72\times 10^{-6}\times 19000}\\\Rightarrow B=-0.07163\hat k\ T$

The magnetic field is 0.07163 T into the page

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2 years ago

A 400-n block is dragged along a horizontal surface by an applied force as shown. the coefficient of kinetic friction is uk = 0.

gulaghasi [49]

The block moves with constant velocity: for Newton's second law, this means that the resultant of the forces acting on the block is zero, because the acceleration is zero.

We are only concerned about the horizontal direction, and there are only two forces acting along this direction: the force F pushing the block and the frictional force $F_f$ acting against the motion. Since their resultant must be zero, we have:
$F-F_f = 0$
The frictional force is
$F_f = \mu mg$
where
$\mu=0.4$ is the coefficient of kinetic friction
$mg=400 N$ is the weight of the block.

Substituting these values, we find the magnitude of the force F:
$F=F_f = \mu mg=(0.4 )(400 N)=160 N$

4 0

2 years ago