BecausE the first 'a' is used with a 'u' making a "ahh" sound
The second 'a' isn't paired with any other vowels so it's sound is a strong A sound
And the 'a' at the end is paired with an 'i' in front of it making an "ee-uhh" sound
plz rate me lol i tried <3
The box is kept in motion at constant velocity by a force of F=99 N. Constant velocity means there is no acceleration, so the resultant of the forces acting on the box is zero. Apart from the force F pushing the box, there is only another force acting on it in the horizontal direction: the frictional force
which acts in the opposite direction of the motion, so in the opposite direction of F.
Therefore, since the resultant of the two forces must be zero,
so
The frictional force can be rewritten as
where
,
. Re-arranging, we can solve this equation to find
, the coefficient of dynamic friction:
Answer:
The amounts will stay the same.
Explanation:
We have a case here. O°C ice into O°C water in an insulated container. The poser here is that what would be the net effect.
It must be highlighted that the insulated container is parody of a constant room temperature and pressure. Meaning all factors are held constant.
Also, a O°C ice is simply the same as a O°C water. Hence, viewing the question under this context, and also acknowledging the constant environment, tells us that the two - Ice and Water at such temperature, will remain unchanged. The effect will be neural.
The underlying factor is that both substances are subjected to same conditions. Hence, the latent kinetic energy and other molecular movements that could occasion will be doing so at same level and frequency. Thus, producing a neutral or almost non different result.
<h2>
a) Initial velocity = 83 ft/s</h2><h2>
b) Object's maximum speed = 99.4 ft/s</h2><h2>
c) Object's maximum displacement = 153.64 ft</h2><h2>
d) Maximum displacement occur at t = 2.59 seconds.</h2><h2>e)
The displacement is zero when t = 5.70 seconds</h2><h2>
f) Object's maximum height = 153.64 ft</h2>
Explanation:
We have velocity
v(t)= -32t + 83
Integrating
s(t) = -16t²+83t+C
At t = 0 displacement is 46 feet
46 = -16 x 0²+83 x 0+C
C = 46 feet
So displacement is
s(t) = -16t²+83t+46
a) Initial velocity is
v(0)= -32 x 0 + 83 = 83 ft/s
Initial velocity = 83 ft/s
b) Maximum velocity is when the object reaches ground, that is s(t) = 0 ft
Substituting
0 = -16t²+83t+46
t = 5.70 seconds
Substituting in velocity equation
v(t)= -32 x 5.70 + 83 = -99.4 ft/s
Object's maximum speed = 99.4 ft/s
c) Maximum displacement is when the velocity is zero
That is
-32t + 83 = 0
t = 2.59 s
Substituting in displacement equation
s(2.59) = -16 x 2.59²+83 x 2.59+46 = 153.64 ft
Object's maximum displacement = 153.64 ft
d) Maximum displacement occur at t = 2.59 seconds.
e) Refer part b
The displacement is zero when t = 5.70 seconds
f) Same as option d
Object's maximum height = 153.64 ft
