Answer:
Hello, the tripping of a 230-kilovolt transmission line.
Explanation:
the tripping of a 230-kilovolt transmission line near Ontario, Canada, at 5:16 p.m., which caused several other heavily loaded lines also to fail. Hopefully this helps you find what your looking for!.
The answer is 24 J
F K =.25*8 N
= 2N
F = f k = 2 N
Since a = 0
W = f * s
2 N * 12 m = 24 J
The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.
For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.
The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.
Learn more about the coefficient of friction here brainly.com/question/20241845
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Answer:
a) T = 2.26 N, b) v = 1.68 m / s
Explanation:
We use Newton's second law
Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string
sin 30 = 
cos 30 = 
Tₓ = T sin 30
T_y = T cos 30
Y axis
T_y -W = 0
T cos 30 = mg (1)
X axis
Tₓ = m a
they relate it is centripetal
a = v² / r
we substitute
T sin 30 = m
(2)
a) we substitute in 1
T = 
T = 
T = 2.26 N
b) from equation 2
v² = 
If we know the length of the string
sin 30 = r / L
r = L sin 30
we substitute
v² = 
v² = 
For the problem let us take L = 1 m
let's calculate
v = 
v = 1.68 m / s
