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Sedbober [7]
4 years ago
11

A tennis ball was thrown into the air with a speed of 22.5 m/s. It was caught at the same height above the ground. a. How fast w

as the ball moving at the peak of its path? b. What was the acceleration on the ball as the ball was moving upward? c. What was the acceleration on the ball as the ball was moving downward? d. What was the acceleration on the ball at the peak of its path? e. How much time was the ball in the air? f. How fast was the ball moving when it was caught?
Physics
1 answer:
Salsk061 [2.6K]4 years ago
8 0
A).  The ball was moving at zero speed at the peak.

b).  The acceleration of the ball was 9.8 m/s² downward, from
the time the hand threw it until the time the hand caught it.

c).  see the answer to b).

d).  see the answer to b).

e).  The ball was in the air for  2 (22.5/9.8) = 4.6 seconds.

f).  The ball was moving down at 22.5 m/s when it was caught.
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If a ball is thrown vertically upward with a velocity of 80 ft/s, then its height after t seconds is s = 80t − 16t 2 . (a) what
MAXImum [283]
Max height occurs when v = 0.
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A fighter plane is flying overhead at mach 1.50. What angle does the wave front of the shock wave produced make relative to the
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Answer:

 θ = 41.80°

Explanation:

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So

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