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A trombone has a variable length. When a musician blows into the mouthpiece and causes air in the tube of the horn to vibrate, t

lana66690 [7]

Answer:

The frequency increases with a shorter horn <em>(Option B)</em>.

Explanation:

The length of the horn determines the distance along which the wave travels; simply called the wavelength. Therefore, a short horn tube will produce a short wavelength and vice versa.

Sound waves have various characteristics that define pitches in musical instruments and these characteristics are interdependent on each other.

in this case, the frequency and the frequency and the wavelength are related.

The relationship between the wavelength and its frequency is given as:

<em>where 'c' is the speed of sound through the instrument; 'f ' is the frequency and 'λ' is the wavelength.</em>

Let's assume that the speed at which the musician blows air into the mouthpiece remains constant, an increase in wavelength will cause a decrease in frequency. Conversely, as the tube of the horn becomes shorter the frequency increases.

6 0

3 years ago

Help awnser physics

kirill115 [55]

Answer:

there I think the answer is measuring tape we cannot use a metre rule because it measures straight lines and I think measuring tape is better because it is flexible thus makes measurement easier

3 0

3 years ago

How can geo thermal energy be used ?

Romashka [77]

Heating and Cooling Using Geothermal Heat, Natural Air Conditioning. Another use of this type of energy is natural cooling.Maintenance of Civil Works. Another direct application is to avoid the freezing of bridges, roads, or airports. .Thermal Waters. For the use of heat in hot springs from geothermal energy, deep waters with temperatures between 40 and 150 ° C are used.

7 0

2 years ago

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After fracture, the total length was 47.42 mm and the diameter was 18.35 mm. Plot the engineering stress strain curve and calcul

Fittoniya [83]

Answer:

Part a: <em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>

Part b: <em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>

Part c: <em>The value of Young's modulus at given point is 172 GPa.</em>

Part d: <em>The percentage elongation is 18.55%.</em>

Part e: The percentage reduction in area is 15.81%

Explanation:

From the complete question the data is provided for various Loads in ductile testing machine for a sample of d0=20 mm and l0=40mm. The plot is drawn between stress and strain whose values are calculated using following formulae. The corresponding values are attached with the solution.

The engineering-stress is given as

$\sigma=\frac{F}{A}\\\sigma=\frac{F}{\pi \frac{d_0^2}{4}}\\\sigma=\frac{F}{\pi \frac{(20 \times 10^-3)^2}{4}}\\\sigma=\frac{F}{3.14 \times 10^{-4}}$

Here F are different values of the load

Now Strain is given as

$\epsilon=\frac{l-l_0}{l_0}\\\epsilon=\frac{\Delta l}{40}\\$

So the curve is plotted and is attached.

<em>The value of yield strength at 0.2% offset is obtained from the engineering stress-strain curve which is given as 274 MPa.</em>

<em>The value of tensile strength is obtained from the engineering stress-strain curve which is given as 417 MPa</em>

Young's Modulus is given as

$E=\frac{\sigma}{\epsilon}\\E=\frac{238 /times 10^6}{0.00138}\\E=172,000 MPa\\E=172 GPa$

<em>The value of Young's modulus at given point is 172 GPa.</em>

The percentage elongation is given as

$Elongation=\frac{l_f-l_0}{l_0} \times 100\\Elongation=\frac{47.42-40}{40}\times 100\\Elongation=18.55 \%\\$

So the percentage elongation is 18.55%

The reduction in area is given as

$Reduction=\frac{A_0-A_n}{A_0} \times 100\\Reduction=\frac{\pi \frac{d_0^2}{4}-\pi \frac{d_n^2}{4}}{\pi \frac{d_0^2}{4}}\times 100\\Reduction=\frac{{d_0^2}-{d_n^2}}{{d_0^2}} \times 100\\Reduction=\frac{{20^2}-{18.35^2}}{{20^2}} \times 100\\Reduction=15.81\%$

So the reduction in area is 15.81%

6 0

3 years ago

In order to increase momentum we must increase either the object's

r-ruslan [8.4K]

C because in order to make something go faster you need to increase it's velocity

6 0

3 years ago

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