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3 years ago

In 1-2 sentences describe how your nose cleans the air you inhale.

1 answer:

3 0

Answer: Your nose inhales O2 and goes through these little nose hairs to keep stuff that doesn't belong in your airway, it goes through your nose into your lungs taking in O2 for your blood. The other substances that you have inhaled get absorbed elsewhere and it is converted into CO2 which is what you exhale.

Explanation:

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Someone please help??

stira [4]

The efficancy is .375

5 0

2 years ago

If the architectural plans show the rough opening of a window to be 3'-3" x 4'-9" , the height of the opening should actually me

tatyana61 [14]

Answer:

height of the opening actually measure is 4'-9"

Explanation:

given data

window size = 3'-3" x 4'-9"

solution

height of the opening should actually measure will be 4'-9" in 3'-3" x 4'-9"

because according to architectural plan height can not be more than the opening size of window

and we can't take smaller height also

so fit in opening window we should take same height of height of opening window and that is here 4'-9"

so here height of the opening actually measure is 4'-9"

5 0

3 years ago

What is the greenhouse effect?

Zanzabum

A on that problem :)[email protected]

6 0

2 years ago

Read 2 more answers

Bob is threatening Tom’s life with a giant laser with wavelength (650 nm), a distance (D = 10 m) from the wall James is shackled

Fittoniya [83]

Answer:

He should stand from the center of laser pointed on the wall at 1.3 m.

Explanation:

Given that,

Wave length = 650 nm

Distance =10 m

Double slit separation d = 5 μm

We need to find the position of fringe

Using formula of distance

$d\sin\theta=n\lambda$

$d\dfrac{y}{D}=n\lambda$

$y=\dfrac{\lambda D}{d}$

Put the value into the formula

$y=\dfrac{650\times10^{-9}\times10}{5\times10^{-6}}$

$y=1.3\ m$

Hence, He should stand from the center of laser pointed on the wall at 1.3 m.

8 0

2 years ago

You and a friend each hold a lump of wet clay. Each lump has a mass of 30 grams. You each toss your lump of clay into the air, w

Vesna [10]

Answer:

$\ \text{m/s}$

Explanation:

$u_1$ = Velocity of one lump = $3x+3y-3z$

$u_2$ = Velocity of the other lump = $-4x+0y-4z$

m = Mass of each lump = $30\ \text{g}$

The collision is perfectly inelastic as the lumps stick to each other so we have the relation

$mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=\ \text{m/s}$

The velocity of the stuck-together lump just after the collision is $\ \text{m/s}$ .

4 0

2 years ago