To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,
The circumference of the planet is,
Under the mathematical value the radius would be
Using second equation of motion
Replacing the values given,
Rearranging and solving for 'a' we have,
Using the value of acceleration due to gravity from Newton's law we have that
Here,
r = Radius of the planet
G = Gravitational Universal constant
M = Mass of the Planet
Therefore the mass of this planet is
<span>The image produced is real and enlarged.
Check for various positions of objects and Images for convex lens.
Note at position of 2F, the image is same as the object, and once it is between 2F and F, the image becomes bigger than the object. </span>
That's the only way you can get consistent and accurate results.
Answer:
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Explanation:
The climate region near the equator with warm air masses is known as tropical. In tropical and polar climates, the weather is consistent throughout the year. In temperate zones, the weather is affected by both warm and cold air masses at different times during the year, so the weather changes with the seasons.
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The diameter of the sphere is 7.5 cm, therefore its volume is
V = [(4π)/3]*(7.5/2 cm)³ = 220.8932 cm³
The density of the lead ball is 11.34 g/cm³, therefore its mass is
m = (220.8932 cm³)*(11.34 g/cm³) = 2.5049 x 10³ g = 2.5048 kg
Answer: 2.5 kg (nearest tenth)