2C2H2(l) +5O2(g)→ 4Co2(g) + 2H2O
The limiting reactant for reaction above is O2
<u><em>explanation</em></u>
The limiting reagent is determined using mole ratio of both reactant.
that is the mole ratio of C2H2:O2 which is 2:5 .
The mole ratio above implies that 37.0 mole of C2H2 needs 37.0 moles x5/2=92 moles of O2.
<em>Since the available moles of O2 was 81.0 mole and 92 moles are required to completely react with C2H2</em><em> ,</em> <u>O2 is the limiting reagent.</u>
7.20594 x 10^20
First you must determine how many moles of P3O5 you have. This is done by using the formula
Number of moles (n) = mass in grams of substance (m) /divided by/ Molar mass (M) [this is the sum of the atomic mass of all atoms in the compound]
n = 0.170 / P (31 x 2) + O (16 x 5)
n = 0.170 / 142
n = 0.001197 moles
Then you use avagadros number 6.02 x10^23 this is the number of atoms in one mole of any substance. Since you have 0.001197 moles you multiply the number of moles by avagadros number
0.001197 x (6.02 x 10^23)
= 7.20594 x 10^20 atoms
T = 2T , P = 2P as given in the question
Volume = mass *density
Now apply ideal gas law
PV=nRT
V = nRT/P
substitute value of V and P
V = nR2T/2P
V =nRT/P
mass*density = nRT/P
density will not change
Answer:
last quarter moon/half moon
Explanation:
