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ahrayia [7]
3 years ago
12

In a synthesis reaction, one reactant contains 346 J of chemical energy, and one reactant contains 153 J of chemical energy. The

product contains 435 J of chemical energy. Because energy is conserved, what energy change occurs during the reaction?
Chemistry
1 answer:
Eduardwww [97]3 years ago
4 0

Answer:

64J of energy must have been released.

Explanation:

Step 1: Data given

One reactant contains 346 J of chemical energy, the other reactant contains 153 J of chemical energy.

The product contains 435 J of chemical energy.

Step 2:

Since the energy is conserved

Sum of energy of Reactants = Energy of Products

Sum of energy of Reactants = 346 J + 153 J = 499 J

The energy of the product = 435 J

435 < 499

This means energy must have been lost as heat.

Step 3: Calculate heat released

499 J - 435 J = 64 J

64J of energy must have been released.

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The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
How many moles of SO3 are in 2.4x10^24 molesculea of SO3
yawa3891 [41]

there are 4.0 moles of SO3

5 0
3 years ago
Balance the chemical equation.Au plus HC l plus HNO 3 right arrow AuC l Subscript 3 Baseline plus NO plus Upper H 2 Upper OAu+HC
tino4ka555 [31]

Answer:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

Explanation:

Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

5 0
3 years ago
What other weapons do sea stars have ?
Harlamova29_29 [7]
None a lot of hand or sum
6 0
3 years ago
Read 2 more answers
3. If the percent by volume is 2.0% and the volume of solution is 250 mL, what is the volume of solute in solution? (1 point) 0.
igor_vitrenko [27]
Volume percent = Volume of solute
                              ----------------------------------
                                Volume of the solution
  
                  2                    Volume of the solute
               -------   =           ------------------------------
                100                               250
                     
         Volume of the solute = 2 x 250
                                                ------------
                                                  100         

                                             =   5 mL.

Hope this helps!




                            




4 0
3 years ago
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