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ahrayia [7]
3 years ago
12

In a synthesis reaction, one reactant contains 346 J of chemical energy, and one reactant contains 153 J of chemical energy. The

product contains 435 J of chemical energy. Because energy is conserved, what energy change occurs during the reaction?
Chemistry
1 answer:
Eduardwww [97]3 years ago
4 0

Answer:

64J of energy must have been released.

Explanation:

Step 1: Data given

One reactant contains 346 J of chemical energy, the other reactant contains 153 J of chemical energy.

The product contains 435 J of chemical energy.

Step 2:

Since the energy is conserved

Sum of energy of Reactants = Energy of Products

Sum of energy of Reactants = 346 J + 153 J = 499 J

The energy of the product = 435 J

435 < 499

This means energy must have been lost as heat.

Step 3: Calculate heat released

499 J - 435 J = 64 J

64J of energy must have been released.

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Explanation:

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Which of the following will lose 2 electrons to become stable?
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Answer:

Magnesium,Berillium,

Explanation:

they they belong to group II

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The atomic notation for a particular atom of boron is 11/5 B. The atomic number is while the mass number is_, while the mass num
Morgarella [4.7K]

The atomic number=5

The mass number=11

<h3>Further explanation</h3>

In the following element notation,

\tt \large {{{A} \atop {Z}} \right X}

 X = symbol of elemental atom

A = mass number

   = number of protons + number of neutrons

Z = atomic number

   = number of protons = number of electrons, on neutral elements

So for The atomic notation for a particular atom of Boron  :

₅B¹¹

Z=5=atomic number

A=11=mass number

5 0
3 years ago
List two examples of carbohydrates and two examples of lipids.
liubo4ka [24]
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Source credit: 
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https://www.thoughtco.com/examples-of-carbohydrates-603884
5 0
4 years ago
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An aqueous solution containing 17.5 g of an unknown molecular compound in 100.g water was found to have a freezing point of-1.8°
Zigmanuir [339]

Answer:

The answer to your question is 178.6 g

Explanation:

Data

ΔT = 1.8 °C

mass = 17.5 g

mass of water = 100 g

Kc = 1.86

Process

1.- Calculate the molality using the following formula

    ΔTc = mKc

solve for m

    m = ΔTc/Kc

substitution

     m = 1.8/1.86

result

     m = 0.968

2.- Calculate the number of moles

    m = # of moles/kg of solvent

kg of solvent = 0.1 kg

     # of moles = m x kg of solvent

     # of moles = 0.968 x 0.1

     # of moles = 0.0968

3.- Calculate the molar mass

        x g molar mass --------------------- 1 mol

       17.5 g                  --------------------- 0.0968 moles

       x = (1 x 17.5)/0.0968

      x = 178.6 g

             

4 0
3 years ago
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