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Answer:
E = 0.062 V
Explanation:
(a) See the attached file for the answer
(b)
Calculating the voltage (E) using the formula;
E = - (2.303RT/nf)log Cathode/Anode
Where,
R = 8.314 J/K/mol
T = 35°C = 308 K
F- Faraday's constant = 96500 C/mol,
n = number of moles of electron = 2
Substituting, we have
E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)
= -0.031 * -2
= 0.062V
Therefore, the voltmeter will show a voltage of 0.062 V
Answer:
Explanation:
The name tells you that this is a binary compound (contains two elements).
It contains a metal and a nonmetal, so it is a binary ionic compound. The general rule is:
Name of compound = name of metal name of ion (two words)
Name of metal = tin(IV), so the tin ion has a charge of 4+
Name of ion = bromide. Br is in Group 17, so bromide ion has charge of 1-.