What is the total charge of an iron nucleus

Draw the structure of tofacitinib with explicitly shown all carbon and hydogen atoms. identify the number of carbon atoms in tof

Andrew [12]

The structure of tofacitinib with explicit carbon and hydrogen is the first attached picture.

The number of carbon atoms in tofacitinib are 16.

The molecular formula of tofacitinib is $C_{16}H_{20}N_{6}O$ .

The structure of tofacitinib with all the filled hydrogen atoms is the second attached picture.

3 0

2 years ago

How does the volume of water change the solubility of sodium chloride in simple words?

kupik [55]

Answer:

When sodium chloride dissolves in water to make a saturated solution there is a 2.5 per cent reduction in volume. ... The solubility of salt does not change much with temperature, so there is little profit in using hot water.

3 0

2 years ago

How does carbon dioxide behave differently (its properties) as a gas compared with as a solid?

ankoles [38]

It is effected by diffusion (the power of smell and wind spread) but a solid is not.

4 0

2 years ago

An electrolytic cell is set up to plate Zr(s) from a solution containing Zr4 (aq). A current of 7.92 amps is run through this so

iren [92.7K]

The mass of Zr deposited in the process is 41.4 g.

<h3>What is electrolytic cell?</h3>

An electrolytic cell is a chemical cell which produces electrical energy by non-spontaneous chemical processes.

From the question;

Zr^4+(aq) + 4e ------> Zr(s)

We know that;

91 g of Zr is deposited by 4(96500) C

xg of Zr is deposited by (7.92 × 6.16 × 60 × 60) C

xg = 91 g × (7.92 × 6.16 × 60 × 60) C/4(96500) C

x g = 41.4 g

Learn more about electrolysis: brainly.com/question/12054569

8 0

1 year ago

From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp

Nina [5.8K]

<u>Answer:</u> The concentration of $NH_3$ required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of $NiC_2O_4$ , we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of $NiC_2O_4$ = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M$

For the given chemical equations:

$NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}$

$Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9$

Net equation: $NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?$

To calculate the equilibrium constant, K for above equation, we get:

$K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48$

The expression for equilibrium constant of above equation is:

$K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}$

As, $NiC_2O_4$ is a solid, so its activity is taken as 1 and so for $C_2O_4^{2-}$

We are given:

$[[Ni(NH_3)_6]^{2+}]=0.016M$

Putting values in above equations, we get:

$0.48=\frac{0.016}{[NH_3]^6}}$

$[NH_3]=0.285M$

Hence, the concentration of $NH_3$ required will be 0.285 M.

7 0

2 years ago