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Mars2501 [29]
2 years ago
10

Living organisms all have DNA and RNA which are both _______

Chemistry
2 answers:
schepotkina [342]2 years ago
7 0
The answer is Nucleic Acids...Hope this was helpful:D
ivanzaharov [21]2 years ago
4 0
Both DNA and RNA are molecules that store genetic information.  
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The energy required to remove an electron from a neutral atom is known as its:
Otrada [13]

Answer:

Ionization energy

Explanation:

4 0
3 years ago
I'm giving 20 points! please it's for a friend not me
astra-53 [7]

Answer:

Three chemical elements: hydrogen, oxygen, and helium.

The difference between metals and metalloids is: metalloids have properties in between those of the metals and non-metals and are semiconductors.

The periodic table is organized by the elemts atomic number, it goes from the element with the lowest atomic number (which is hydrogen) to the element with the highest atomic number (oganesson)

Explanation:

Hope this helps :)

6 0
2 years ago
Which shows the correct relationship between the molecular formula and the empirical formula for C2H10N2?
SIZIF [17.4K]
The correct answer is A. molecular formula = 2 x empirical formula

The given compound C2H10N2 is the molecular formula because the ratios of the elements are not reduced into lowest terms (empirical formula). To get the empirical formula, the ratios must be reduced to the smallest possible integral ratio which gives CH5N. As a result, the ratio between both formulas is 2.
3 0
2 years ago
Read 2 more answers
HEY I NEED ALL ANSWERS RIGHT NOW IT'S MISSING AND MY TEACHER ARE GRADING THEM NOW YOU WILL BE MARKED BRAINIEST
emmainna [20.7K]

Molar mass of butane:-

  • 4(12)+10=58u

Moles of Butane:-

  • 100/58=1.7mol

#16

  • 2mols of Butane produce 8mol CO_2
  • 1mol of butane produces 4mol CO_2

Moles of CO_2

  • 4(1.7)=6.8mol

Mass of CO_2:-

  • 44(6.8)=299.2g

#17

  • 2mols of butane need 13mol O_2
  • 1mol of butane needs 6.5mol O_2

Moles of O_2

  • 6.5(1.7)=11.05mol

Mass of O_2

  • 11.05(32)=353.6g
7 0
2 years ago
For the reaction of hydrogen with iodine
fenix001 [56]

Answer:

r_{H_2} = \frac{-1}{2} r_{HI}

Explanation:

Hello!

In this case, considering the given chemical reaction:

H_2(g) + I_2(g) \rightarrow 2HI(g)

Thus, by applying the law of rate proportions, we can write:

\frac{1}{-1} r_{H_2} = \frac{1}{-1}r_{i_2} = \frac{1}{2} r_{HI}

Whereas the stoichiometric coefficients of reactants are negative due their disappearance and that of the product is positive due to its appearance. In such a way, when we relate the rate of disappearance of hydrogen gas to the rate of formation of hydrogen iodide, we obtain:

r_{H_2} = \frac{-1}{2} r_{HI}

Best regards!

8 0
2 years ago
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