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frez [133]
2 years ago
10

Explain sp hybridization in acetylene molecule? Dr

Chemistry
1 answer:
Nikolay [14]2 years ago
6 0
This is very confusing
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babunello [35]

Answer:

you are right

Explanation:

and i do not need to explain it because you did

8 0
3 years ago
Pleaseeee helpppp thank youu​
Gemiola [76]

<em>Answer:</em>

<h3><em>Answer:</em><em> </em><em>well</em><em> </em><em> </em></h3>

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2 years ago
How do you dilute a concentrated solution?
AVprozaik [17]

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add more water

Explanation:

5 0
3 years ago
A liquid that evaporates at a slow rate exhibits __________.
Marizza181 [45]
Strong internolecurar forces (A) hope it helps
3 0
3 years ago
A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t
andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)

So, moles of product formed are calculated as follows.

\frac{3}{2} \times 0.17 mol \\= 0.255 mol

Hence, the given data is as follows.

n_{1} = 0.17 mol,      n_{2} = 0.255 mol

V_{1} = 19.5 L,         V_{2} = ?

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0
2 years ago
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