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3 years ago

Explain sp hybridization in acetylene molecule? Dr

Chemistry

1 answer:

Nikolay [14]3 years ago

6 0

This is very confusing

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Help! ASAP! Please on the questions

KiRa [710]

Answer:

62.15 m (squared)

Explanation:

We know that the Area of the square is 5.5 x 4= 22

so 90 degree to 30 degree is divide by 3

so u divide 22 by 3 and get 7.3 wich is the semi circle thing

now 7.3 x 5.5 = 40.15

22 + 40.15 = 62.15 m (squared)

Look im not really sure but I think this is the answer

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Thank u

8 0

3 years ago

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Does the amount of power Change going up a fight of steps as I Change my speed?

Leviafan [203]

yes because your going faster

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3 years ago

Is aluminum a liquid at 1000 kelvin

daser333 [38]

Yes you are correct

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3 years ago

If you were to compare a cell to the human body, what organ in the body would have a similar responsibility to the cells nucleus

Amanda [17]

The brain. The brain tells the body what to do same way the nucleus does for the cell.

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2 years ago

A sheet of polyethylene 1.5-mm thick is being used as an oxygen barrier at a temperature of 600K. If the flux is 2.48 x 10-5 kg/

Eddi Din [679]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of high-pressure side is $C_1 = 0.722 \ kg/m^3$

Explanation:

From the question we are told that

The thickness of the polyethylene is $d = 1.5 \ mm = 0.0015 \ m$

The temperature is $T = 600 \ K$

The flux is $JA = 2.48 *10^{-5} \ kg/m^2\cdot s$

The concentration on the low-pressure side is $C_2 = 0.5 \ kg/m^3$

The initial diffusivity is $D_o = 6.2 *10^{-4} \ m^2 /s$

The activation energy for diffusion is $Q_d = 41 \ kJ /mol = 41*10^3 J /mol$

Generally the diffusivity of the oxygen at 600 K can be mathematically evaluated as

$D = D_o * e^{- \frac{Q_d}{R * T } }$

substituting values

$D = 6.2*10^{-4} * e^{- \frac{41 *10^3}{8.314 * 600 } }$

$D = 1.671 *10^{-7} \ m^2 /s$

Generally the flux is mathematically represented as

$JA = D * \frac{C_1 -C_2}{d}$

Where $C_1$ is the concentration of oxygen at the higher side

$C_1 = d * \frac{JA}{D} + C_2$

substituting values

$C_1 = 0.0015 * \frac{2.48*10^{-5}}{1.671*10^{-7}} + 0.5$

$C_1 = 0.722 \ kg/m^3$

6 0

3 years ago