This is a case of metric system of measurements. The scale of the metric system only differs by a factor of 10. The scale (from greatest to least) is kiloliter, hectoliter, dekaliter, liter, deciliter, centiliter and milliliter. If the unit is 150 dL, and you want to find the equivalent dkL measurement, just move the decimal point 2 decimals places to the left (just follow the scale). The same procedure is done for the other metric units.
150 dL = 1.5 dkL
150 dL = 15 L
150 dL = 1,500 cL
150 dL = 15,000 mL
From the choices, the answer is letter C.
Answer:
كىتى
Explanation:
ؤكىتسؤكى سكتؤىسى شؤت سؤتنى،آ}تسى}
% by mass = (mass solute/mass solution)*100%
mass of the solute = 54.7 g
mass of the solution = mass solute + mass solvent=54.7+500=554.7 g
% by mass = (54.7/554.7)*100%≈0.0986*100% = 9.86%
Answer:
a) 
b) 
c) 
Carbon: 
Explanation:
<u>Nitrate</u>
First of all, is important to know that:

a) 10 ppm of nitrate (
) is equal to 
b) The molecular weight of nitrate is 


c) Nitrate has 14 mg of N per 62 mg of NO3

<u>Carbon</u>
Carbonate has 12 mg of C per 60 mg of 
Bicarbonate has 12 mg of C per 61 mg of 

