Cole ate grass and weed while lying after attack
1) k2O = 2K(1+) + O(2-)
This is, every molecule of K2O consists of three ions (2 of K 1+, and one of O 2-)
2) Caluclate the number of moles of K2O
- molar mass of K2O = 2*39 + 16 = 94 g/mol
- n = mass / molar-mass = 9.4g / 94 g/mol = 0.1 mol
3) Multiply by 3 to have the number of moles of ions: 3 *0.1 mol = 0.3 mol of ions.
4) Multiply by Avogadro's number to obtain the number of ions"
0.3 mol * 6.0*10^23 =1.8 * 10^23 ions.
Answer: 1.8*10^23 ions
Answer:
your teeth will rot so will your lungs
Answer:
1.39 g
Explanation:
1.39 g
Mass magnesium oxide = 3.78 g. So mass oxygen = 1.39 g. Number moles Mg = 2.39/24 = 0.0995. Number moles O = 1.39/16 = 0.0868.
Because I (iodide) is better leaving group than Cl, so it will leave when this molecule is reacted with strong base (sodium tert-butyl oxide) giving the elimination product provided in picture<span />