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serg [7]
3 years ago
5

An opening volumetric cylinder filled with water at volume 0.003m after period of

Chemistry
1 answer:
raketka [301]3 years ago
7 0

Answer:

= - 303.975 Joules

Explanation:

Given that:

The volume of the cylinder = 0.003 m^3

Now, to liters:

The volume = 0.003 *1000 L

= 3 L

For an open cylinder, we mean the atmospheric pressure is at standard condition.

Thus, the workdone = -PΔV

= - 1 atm (3 L)

= - 3 L atm

1 L atm to Joules

= 101.325 Joules

Therefore;

=- 3* 101.325 Joules

= - 303.975 Joules

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vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

pH = 3.85

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pOH = 10.15

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pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

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Explanation:

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Explanation:

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