When the speed of the particle is close to that of light, it's observed mass would be infinitely large.
To answer the question, we need to know what observed mass is.
<h3>What is observed mass in relativity?</h3>
This is the mass the body of an object in relativistic motion appears to have.
So, observed mass, m' = m/√(1 - β²) where
- m = rest mass and
- β = relative velocity of isotope to light.
Now, since the speed of the particle is close to that of light, β ≅ 1.
So, m' = m/√(1 - β²)
m' = m/√(1 - 1²)
m' = m/√(1 - 1)
m' = m/√0
m' = m/0
m' = ∞
So, when the speed of the particle is close to that of light, it's observed mass would be infinitely large.
Learn more about observed mass here:
brainly.com/question/14553472
Answer: 0.66 g/mL
Explanation: The formula for density is d= m/v where m=mass and v=volume.
The mass was given in the problem, m= 1.32kg
The volume was also given in the problem, v= 2.0L
d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L
The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.
1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).
The atomic mass of Aluminum is around 27 amu. There are two aluminum atoms, so it takes 54 amu. The gram-formula states that 1 mole of this compound has 342 grams. By definition, this means that the total amu of this compound is 342. Therefore, we divide 54 by 342 to get around 15.8 %.
In exothermic reactions, there is a release heat and the replacement of weak bonds with stronger ones.
Answer:
The volume is increased.
Explanation:
According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;
V₁ / T₁ = V₂ / T₂ -----(1)
In statement the data given is,
T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C
T₂ = 20 °C = 293.15 K
So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,
V₁ = 100 L
V₂ = Unknown
Now, we will arrange equation 1 for V₂ as,
V₂ = V₁ × T₂ / T₁
Putting values,
V₂ = 100 L × 293.15 K / 283.15 K
V₂ = 103.52 L
Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.
