Before taking the derivatives of the function, simplify the equation first for smooth operation.
x^6 + y^6 = 1
Multiply the whole equation with an exponent of 1/6 for uniformity. This would get rid of the exponents of x and y. The product would be
x + y = 1^1/6
x + y = 1
Expressing in terms of x:
y = 1 - x
Now, we derive the equation:
y' = 0 -1 = -1
y" = 0
Answer: I think it is b
Step-by-step explanation:
Need points, don’t use this
Answer is A
Answer:
Attachment
Step-by-step explanation:
x = 0
y = | 0 + 4 | - 1
y = 4 - 1
y = 3
y = 0
0 = | x + 4 | - 1
1 = | x + 4 |
x + 4 = 1 => x₁ = 1 - 4 => x₁ = - 3
x + 4 = - 1 => x₂ = - 1 - 4 => x₂ = - 5
Hello from MrBillDoesMath!
Answer:
The fourth choice, b = +\- sqrt( sg + a^2)
Discussion:
s = (b^2 - a^2)/g => multiply both sides by "g"
sg = b^2 - a^2 => add a^2 to both sides
sg + a^2 = b^2 => take the square root of each side
b = +\- sqrt( sg + a^2)
which is the fourth choice.
Thank you,
MrB
