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insens350 [35]
3 years ago
5

What is the domain of f(x) = 3x - 2?

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0

Answer:

{x\x is a real number}

Step-by-step explanation:

I think that is.

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Select the expression that shows the application of the distributive property for
sergeinik [125]

Answer:

c. 9t+45 that shows distributive property

where it shows a*(b+c)=(a*b)+(b*c).so,9(t+5)=9*t+9*5

8 0
2 years ago
VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
Assoli18 [71]
I believe it’s B.) sorry if I’m wrong!!!!
5 0
3 years ago
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Please Help ASAP
Tju [1.3M]

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The discriminant is ...

  b^2 -4ac = (-4)^2 -4(2)(16) = 16 -128 = -112

A negative discriminant means there are no real solutions to the equation.

_____

The complex solutions are 1±i√7.

If we assume the equation has a typographical error and is intended to be ...

  2x^2 -4x -16 = 0

The solutions are x = -2 and x = 4.

3 0
3 years ago
If a triangle has three congruent angles, then it is equilateral.
Zielflug [23.3K]

I believe the answer is A "If a triangle is equilateral, then it has three congruent angles". Hope this helps!

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3 years ago
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If two objects travel through space along two different curves, it’s often important to know whether they will collide. (Will a
galina1969 [7]

Answer:

<em>Both objects collide at t=3 in the point  <9,9,9></em>

Step-by-step explanation:

<em>Collision Of Moving Objects </em>

Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.

The positions of two object are given as

r1(t)=

r2(t)=

Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both

t^2=4t-3

Rearranging

t^2-4t+3=0

Factoring

(t-1)(t-3)=0

We found two solutions

t=1,\ t=3

for t=1 the x-coordinates are

x1=t^2=1

x2=4t-3=1

For t=3

x1=t^2=9

x2=4t-3=9

Now we'll test both values in the y-coordinates

y1=7t-12

y2=t^2

For t=1

y1=-5

y2=1

Thus they don't collide at t=1. Let's try t=3

y1=7(3)-12=9

y2=3^2=9

Now let's try the z-coordinate for t=3

z1=t^2=9

z2=5t-6=9

Since the three coordinates match, we can say both objects collide at t=3 in the point  <9,9,9>

6 0
4 years ago
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