Answer:
1984
Explanation:
Given the formula;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2 = half life of the radioactive isotope
t= age of the wine
Ao= initial activity of the wine
A= activity of the at time = t
0.693/12.3 = 2.303/t log (5.5/0.688)
0.693/12.3 = 2.079/t
0.056 = 2.079/t
t= 2.079/0.056
t= 37 years
The wine was produced 37 years ago which means that it was produced in the year 1984
The end pH will be 7 if the acid and base were added in the correct amounts in relation to each other.
general formula:
HA+BOH⇒H₂O+AB (AB is the salt produced from the anion in the acid and cation in the base)
Answer:
Passivation of Oxide layers of the metals.
Explanation:
Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.
Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.
Answer: Link in Explaination will help you!! :)
Explanation: https://otherhalf.life/image.php?id=IYZMDN.pdf
Answer:
In the formation of diazonium ion intermediate, the <em><u>4-sulfanilic acid acts as the Lewis acid</u></em>, while the <em><u>sodium nitrite is the Lewis base.</u></em>
Explanation:
A Lewis acid is by definition an electron pair acceptor (such as the H+ ion, that can accept a pair of non-bonding electrons) and a Lewis base is an electron pair donor (such as the OH- ion, that can donate a pair of non-bonding electrons).
In the formation of diazonium ion intermediate, the 4-sulfanilic acid acts as the Lewis acid(by transference of a lone pair from its nitrogen atom), while the sodium nitrite is the Lewis base.
<em>N.B </em><em>its sodium nitrite, NaNO2 (which is slightly basic in solution) not nitrate NaNO3 (which is neutral in solution)</em>