A cactus would probably be the kind of vegitation you would find
Answer:
The wheel has turned θ= 4.84 rad when its angular speed is ωf= 2.1 rad/s
Explanation:
ωi= 3.4 rad/s
ωf= 2.1 rad/s
α= - 0.736 rad/s²
ωf= ωi - α*t
(ωf-ωi)/α=t
t= 1.76 s
θ= ωi * t - α * t²/2
θ= 4.84 rad
Answer:
1.78 J
Explanation:
Find the spring coefficient using Hooke's law:
F = k Δx
23 N = k (0.20 m − 0.14 m)
k = 383.33 N/m
The work is the change in energy:
W = PE₂ − PE₁
W = ½ kx₂² − ½ kx₁²
W = ½ k (x₂² − x₁²)
W = ½ (383.33 N/m) ((0.17 m)² − (0.14 m)²)
W = 1.78 J
Answer: P = 25050.8w
Explanation:
total energy at top = K.E + P.E
= (1/2)(6861)(100) + 6861(9.81)(142)
total energy at bottom
= (1/2)(6861)(48)^2
work done = energy at top - energy at bottom
average velocity = (48+10)/2
time = 2300/average velocity
power = work done/time
plus potential) at the base and the top; is the energy input from the engine
the ascent time is the average speed, (top + bottom) / 2; divided by the 2.3 km distance
energy / time equals power