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3 years ago

14

Automobile engines AND steam engines are examples of ______. a. internal combustion engines b. heat engines c. external combusti

on engines d. solar collectors

2 answers:

uranmaximum [27]3 years ago

8 0

Answer: B. Heat engines

Explanation:

icang [17]3 years ago

4 0

Answer:

your answer should be a. steam engines

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Physics Homework

katrin2010 [14]

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled. Displacement is the difference between the final position and initial position.

4 0

4 years ago

A 15.0-kg block is dragged over a rough, horizontal surface by a 70.0-N force acting at 20.0° above the horizontal. The block is

Tatiana [17]

Answer:

Explanation:

from the question we are told that

Load $L=15kg$

Force $F=70N$

Angle of inclination $=20.0 degres$

Displacement $m=5 meters$

coefficient of kinetic friction $\alpha =0.300$

3 0

3 years ago

An actor who memorizes his lines word-for-word has demonstrated _____ learning.

Nana76 [90]

<span>Mechanical association learning used by an actor to memorize his lines</span>

8 0

3 years ago

Read 2 more answers

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh

frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

$y\propto x^{1.25}$

$y=kx^{1.25}$

$k=\dfrac{y}{x^{1.25}}$

Put the value into the formula

$k=\dfrac{1.8}{1.1^{1.25}}$

$k=1.5978$

We need to calculate the crab weight

$y=kx^{1.25}$

Here, x = 0.85 g

Put the value into the formula

$y=1.5978\times(0.85)^{1.25}$

$y=1.3040\ gram$

Hence, The weight of body is 1.3040 gram.

7 0

4 years ago

29) A load is placed on a 1.5-kg cart. A force of

Goryan [66]

Answer: 0.5 kg
Check photo for work

3 0

3 years ago