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Orlov [11]
3 years ago
8

50 pounds is equal to 22,700 grams. How many pounds does this backpack full of gold weigh? Would you be able to carry out that b

ackpack filled with gold?
Physics
1 answer:
Mariulka [41]3 years ago
4 0

The question is incomplete. Here is the complete question.

7) A standard backpack is approximately 30cm x 30cm x 40cm. Suppose you find a hoard of pure gold (density = 19.3 g/cm³) while treasure hunting in the wilderness. How much mass would your backpack hold if you filled it with gold?

8) 50 pounds is equal to 22,700 grams. How many pounds does this backpack full of gold weigh? Would you be able to carry out that backpack filled with gold?

Answer: 7) m = 694,800g

              8) It wieghts 1530.4 lbf

Explanation:

7) Volume of the backpack will be

V = 30 x 30 x 40

V = 36000 cm³

According to density of gold, each cm³ corresponds to 19.3g, then:

m = 19.3\frac{g}{cm^{3}} * 36000cm³

m = 694800g

If I filled it with gold, the backpack will hold 694800g or 694.8kg.

8) 50 pounds is equal to 22700g. Then:

50 pound = 22700g

W = 694800g

W = \frac{694800.50}{22700}

W = 1530.4 lbf

The backpack, in pounds, will weigh 1530.4lbf, which is very heavy to be supported by a human body.

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The length of the assembly decreases by 0.006 in. when an axial a- force is applied by means of rigid end plates. Determine
Triss [41]

Answer:

(a) The magnitude of the applied force is (0.0001524k) Newton

(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square

Explanation:

(a) From Hookes law of elasticity,

Force applied = force constant (k) × compression

compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter

Force applied = k × 0.0001524 = (0.0001524k) Newton

(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square

6 0
3 years ago
A 129-kg horizontal platform is a uniform disk of radius 1.61 m and can rotate about the vertical axis through its center. A 65.
LUCKY_DIMON [66]

Answer:

Moment of inertia of the system is 289.088 kg.m^2

Explanation:

Given:

Mass of the platform which is a uniform disk = 129 kg

Radius of the disk rotating about vertical axis = 1.61 m

Mass of the person  standing on platform = 65.7 kg

Distance from the center of platform = 1.07 m

Mass of the dog on the platform = 27.3 kg

Distance from center of platform = 1.31 m

We have to calculate the moment of inertia.

Formula:

MOI of disk = \frac{MR^2}{2}

Moment of inertia of the person and the dog will be mr^2.

Where m and r are different for both the bodies.

So,

Moment of inertia (I_y_y )  of the system with respect to the axis yy.

⇒ I_y_y=I_d_i_s_k + I_m_a_n+I_d_o_g

⇒ I_y_y=\frac{M_d_i_s_k(R_d_i_s_k)^2}{2} +M_m(r_c)^2+M_d_o_g(R_c)^2

⇒ I_y_y=\frac{129(1.61)^2}{2} +65.7(1.07)^2+27.2(1.31)^2

⇒ I_y_y=289.088\ kg.m^2

The moment of inertia of the system is 289.088 kg.m^2

7 0
3 years ago
Tire or false
spayn [35]
1 and 4 are tire.
2 and 3 are not.
8 0
3 years ago
An object begins with a speed of 20 meters per second and slows down to a speed of 10 meters per second over a time of 5 seconds
Andreyy89

Answer:

V = 6 m/s

Explanation:

Given that,

Initial speed of an object is 20 m/s

Final speed of an object is 10 m/s

Time, t = 5 s

We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

V=\dfrac{x+y}{2}\\\\\text{Putting values}\\\\V=\dfrac{20+10}{5}\\\\V=6\ m/s

So, the average speed of the object is 6 m/s.

3 0
3 years ago
The average velocity for a trip has a positive value. Isit
Luba_88 [7]

Answer:

Yes, it's possible.

Explanation:

The average velocity is a mean value:

Vavg=\frac{displacement}{time taken}.

during that displacement, it may occur that the acceleration would negative at any time so at that moment if the velocity goes in the same direction with the acceleration, the velocity will be negative, it may take just a few moments and then go positive again. The velocity can also take negative values if for a moment the object was going backward (opposite direction). so the average velocity only means that the major of the velocity was positive.

5 0
4 years ago
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