Answer:
<em>b. At twice the distance, the electric potential is V/2</em>
Explanation:
Electric potential
Is the amount of work needed to move a unit charge from a reference point (usually a point at infinity) without producing acceleration.
The electric potential due to a point charge q at a distance r is given by
Where K is the Coulomb's constant. If we know the electric potential at a certain distance is V, if the distance is changed to 2r, then the new potential is
It means that the electric potential is half the previous value. Correct option: b.
Answer:
C i think sorry if inmccorect
Explanation:
D=m÷v
so density would be 57.9 ÷ 3 = 19.3 g/cm³
So the problem are asking to find the value of G base on the formula of the said equation of the magnitude of gravitational attraction on either body. Base on that, the possible answer or the derived formula of the said function is G = Fr^2/m1m2. I hope you are satisfied with my answer and feel free to ask for more