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nekit [7.7K]
3 years ago
11

Avg velocity definition | Problem Average velocity vectors…

Physics
1 answer:
Aneli [31]3 years ago
3 0

Answer:

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

Explanation:

As we know that average velocity is defined as the ratio of change in position and the time interval of the object

It is given as

v_{avg} = \frac{\Delta x}{\Delta t}

so we will have

\Delta x = displacement

\Delta t = time interval

the direction is this average velocity is always along the direction of the displacement

so correct answer will be

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

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The answer is c because the farther apart they are the greater there gravity is
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3 years ago
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A 5kg box is being pulled for a force of 20 n and is sliding with an acceleration of 2 m/s. Find the coefficient of friction
RUDIKE [14]

Answer:

Coefficient of friction = 0.5

Explanation:

Given:

Mass of box = 5 kg

Force applied = 20 N

Acceleration = 2 m/s²

Find:

Coefficient of friction

Computation:

Friction force = Mass x Acceleration.

Friction force =  5 x 2

Friction force = 10 N

Coefficient of friction = Friction force / Force applied

Coefficient of friction = 10 / 20

Coefficient of friction = 0.5

3 0
2 years ago
If a vehicle accelerating at 2.7 m/s2what is it's velocity at 20 meters 12.63m/s,1.03m/s,10.39m/s,6.39m/s
netineya [11]

Answer:

The final velocity of the vehicle is 10.39 m/s.

Explanation:

Given;

acceleration of the vehicle, a = 2.7 m/s²

distance moved by the vehicle, d = 20 m

The final velocity of the vehicle is calculated using the following kinematic equation;

v² = u² + 2ah

v² = 0 + 2 x 2.7 x 20

v² = 108

v = √108

v = 10.39 m/s

Therefore, the final velocity of the vehicle is 10.39 m/s.

5 0
3 years ago
A force of 14 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching i
enyata [817]

Answer:

W = 19.8 J

Explanation:

14 lb force is required to stretch the spring by 4 inch distance

So we have

F = 14 lbf

F = 6.35 \times 9.8 N

F = 62.3 N

stretch in the spring is given as

x = 4 in = 0.1016 m

now we will have

F = kx

62.3 = k(0.1016)

k = 613.125 N/m

Now we need to find the work to stretch it by x = 10 in = 0.254 m

so we have

W = \frac{1}{2}kx^2

W = \frac{1}{2}(613.125)(0.254)^2

W = 19.8 J

7 0
3 years ago
As you ride a bicycle on the sidewalk with a speed of
mixer [17]

Answer:

1.2 seconds

Explanation:

distance = ((final speed + initial speed) * time)/2

Here given:

  • distance: 3.8 meter
  • initial speed: 6.4 m/s
  • final speed: 0 m/s

Solving steps:

3.8 = ((0 + 6.4) * time))/2

3.8 = 3.2(time)

time = 3.8/3.2

time = 1.1875 seconds ≈ 1.2 seconds

5 0
1 year ago
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