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3 years ago

Avg velocity definition | Problem Average velocity vectors…

Physics

1 answer:

Aneli [31]3 years ago

3 0

Answer:

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

Explanation:

As we know that average velocity is defined as the ratio of change in position and the time interval of the object

It is given as

$v_{avg} = \frac{\Delta x}{\Delta t}$

so we will have

$\Delta x$ = displacement

$\Delta t$ = time interval

the direction is this average velocity is always along the direction of the displacement

so correct answer will be

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

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A kid drops 1.2kg heavy ball vertically down. The ball hits ground and vertically bounce back. Speeds of the ball just before an

iVinArrow [24]

Answer:

8400 N

Explanation:

We are given that

Mass,m=1.2 kg

Initial speed,u=-8 m/s

Final speed,v=6 m/s

Time, $\Delta t=2 ms=2\times 10^{-3} s$

$1 ms=10^{-3} s$

We have to find the magnitude of the average force on the ball during this collision.

Change in momentum,= $\Delta p=m(v-u)=1.2(6+8)=16.8 kgm/s$

Average force, $F_{avg}=\frac{\Delta p}{\Delta t}$

Using the formula

$F_{avg}=\frac{16.8}{2\times 10^{-3}}=8400 N$

Hence, the magnitude of the average force on the ball during this collision=8400 N

8 0

4 years ago

tom and huck are pulling a table in the same direction at the same time with 7N of force each,what is the net force acting on th

defon

We have that The net force acting on the table is

Fn=14N

From the question we are told

tom and huck are pulling a table in the same direction at the same time with 7N of force each,what is the net force acting on the table

Generally the equation for the Net Force is mathematically given as

Fn=Toms Force +Hucks Force

Therefore

Fn=7+7

Fn=14N

In conclusion

The net force acting on the table is

Fn=14N

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3 years ago

Make a prediction based on your understanding of the cause-and-effect relationship between environment and trait: what happens w

Rom4ik [11]

Everything dies because it’s to extreme

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3 years ago

Why cant you feel the force attraction between mars

Ludmilka [50]

The distance is too great for the attraction to make a difference

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3 years ago

Two children, Ferdinand and Isabella, are playing with a waterhose on a sunny summer day. Isabella is holding the hose in herhan

AVprozaik [17]

Answer:

84%

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

$y_0=1\ m$

x = 10 m

t = Time taken

$v_0$ = 3.5 m/s (assumed, as it is not given)

$A_0=\pi 1.5^2$

We have the equation

$y=y_0+ut+\dfrac{1}{2}gt^2\\\Rightarrow 0=y_0-\dfrac{1}{2}gt^2\\\Rightarrow t=\sqrt{\dfrac{2y_0}{g}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1}{9.81}}\\\Rightarrow t=0.45152\ s$

$x=x_0+vt\\\Rightarrow 10=0+v0.45152\\\Rightarrow v=\dfrac{10}{0.45152}\\\Rightarrow v=22.14741\ m/s$

From continuity equation we have

$Av=A_0v_0\\\Rightarrow A=\dfrac{A_0v_0}{v}\\\Rightarrow A=\dfrac{\pi 1.5^2\times 3.5}{22.14741}\\\Rightarrow A=1.11706\ cm^2$

Fraction is given by

$f=\dfrac{A_0-A}{A_0}\times 100\\\Rightarrow f=\dfrac{\pi 1.5^2-1.11706}{\pi 1.5^2}\times 100\\\Rightarrow f=84.196\ \%\approx 84\ \%$

The fraction is 84%

8 0

3 years ago