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2 years ago

Avg velocity definition | Problem Average velocity vectors…

Physics

1 answer:

Aneli [31]2 years ago

3 0

Answer:

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

Explanation:

As we know that average velocity is defined as the ratio of change in position and the time interval of the object

It is given as

$v_{avg} = \frac{\Delta x}{\Delta t}$

so we will have

$\Delta x$ = displacement

$\Delta t$ = time interval

the direction is this average velocity is always along the direction of the displacement

so correct answer will be

point in the same direction as the change in position.

require knowing the initial and final position, along with the elapsed time.

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In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the s

puteri [66]

Answer:

the correct answer is A

Explanation:

In an Einstein-type analysis, the photon is absorbed, it loses all its energy, therefore the electron must receive all or none of the energy of the incident photon. In a type of inelastic shock.

Let's analyze the different answers

A) true. In photon it is completely absorbed or passes without interaction

B) False. The photon must change energy, but in this case there is no absorption of the photon

C) False. In the insistent analyzes, the quantization of the electron in discrete states is not mentioned.

Therefore the correct answer is A

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2 years ago

Astronauts use a centrifuge to simulate the acceleration of a rocket launch. The centrifuge takes 40.0 s to speed up from rest t

Vinvika [58]

Answer

Time period T = 1.50 s

time t = 40 s

r = 6.2 m

Angular speed ω = 2π/T

= $\dfrac{2\pi }{1.5}$

= 4.189 rad/s

Angular acceleration α = $\dfrac{\omega}{t}$

= $\dfrac{4.189}{40}$

= 0.105 rad/s²

Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²

b)The maximum speed.

v = 2πr/T

= $\dfrac{2\pi \times 6.2}{1.5}$

= 25.97 m/s

So centripetal acceleration.

a = $\dfrac{v^2}{r}$

= $\dfrac{25.97^2}{6.2}$

= 108.781 m/s^2

= 11.1 g

in combination with the gravitation acceleration.

$a_{total} = \sqrt{(11.1g)^2+g^2}$

$a_{total}= 11.145 g$

6 0

3 years ago

A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t

WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

$v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s$

So, the required time is 2.2 seconds.

3 0

2 years ago

Based on the replacement reaction, what would the products of the reaction be?

cricket20 [7]

Answer:

$\rm Be(OH)_2$ and $\rm (NH_4)_2 SO_4$ . The missing ion would be $\rm OH^{-}$ .

Explanation:

In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.

In this question, the two ionic compounds are:

$\rm BeSO_4$ , and
$\rm NH_4 OH$ .

In particular,

$\rm BeSO_4$ is made up of $\rm Be^{2+}$ ions and $\rm {SO_4}^{2-}$ ions, while
$\rm NH_4 OH$ is made up of $\rm {NH_4}^{+}$ ions and $\rm OH^{-}$ ions.

In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)

$\rm Be^{2+}$ is a cation. In $\rm BeSO_4$ , $\rm Be^{2+}$ was bounded $\rm {SO_4}^{2-}$ anions. During the reaction, it bonds with $\rm OH^{-}$ anions to produce $\rm Be(OH)_2$ .

$\rm {NH_4}^{+}$ is also a cation. In $\rm NH_4 OH$ , $\rm {NH_4}^{+}$ was bounded to $\rm OH^{-}$ ions. During the reaction, it bonds with $\rm {SO_4}^{2-}$ anions to produce $\rm (NH_4)_2 SO_4$ .

Hence, the two products will be $\rm Be(OH)_2$ and $\rm (NH_4)_2 SO_4$ .

Note that charges on the ions must balance. For example, a $\rm Be^{2+}$ ion carries twice as much charge as an $\rm {NH_4}^{+}$ ion. As a result, each $\rm Be^{2+}$ ion would bond with twice as many $\rm OH^{-}$ ions as $\rm {NH_4}^{+}$ would in $\rm NH_4 OH$ .

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3 years ago

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Which type of training will improve muscular strength?

mojhsa [17]

Answer:

Explanation:

Lifting heavy weights every day

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2 years ago