The answer is c because the farther apart they are the greater there gravity is
Answer:
Coefficient of friction = 0.5
Explanation:
Given:
Mass of box = 5 kg
Force applied = 20 N
Acceleration = 2 m/s²
Find:
Coefficient of friction
Computation:
Friction force = Mass x Acceleration.
Friction force = 5 x 2
Friction force = 10 N
Coefficient of friction = Friction force / Force applied
Coefficient of friction = 10 / 20
Coefficient of friction = 0.5
Answer:
The final velocity of the vehicle is 10.39 m/s.
Explanation:
Given;
acceleration of the vehicle, a = 2.7 m/s²
distance moved by the vehicle, d = 20 m
The final velocity of the vehicle is calculated using the following kinematic equation;
v² = u² + 2ah
v² = 0 + 2 x 2.7 x 20
v² = 108
v = √108
v = 10.39 m/s
Therefore, the final velocity of the vehicle is 10.39 m/s.
Answer:

Explanation:
14 lb force is required to stretch the spring by 4 inch distance
So we have



stretch in the spring is given as

now we will have



Now we need to find the work to stretch it by x = 10 in = 0.254 m
so we have



Answer:
1.2 seconds
Explanation:
distance = ((final speed + initial speed) * time)/2
Here given:
Solving steps:
3.8 = ((0 + 6.4) * time))/2
3.8 = 3.2(time)
time = 3.8/3.2
time = 1.1875 seconds ≈ 1.2 seconds