Avg velocity definition | Problem Average velocity vectors…
1 answer:
Answer:
point in the same direction as the change in position.
require knowing the initial and final position, along with the elapsed time.
Explanation:
As we know that average velocity is defined as the ratio of change in position and the time interval of the object
It is given as
so we will have
= displacement
= time interval
the direction is this average velocity is always along the direction of the displacement
so correct answer will be
point in the same direction as the change in position.
require knowing the initial and final position, along with the elapsed time.
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Answer:
The width of the slit is 0.167 mm
Explanation:
Wavelength of light,
Distance from screen to slit, D = 88.5 cm = 0.885 m
The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m
We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :
where
a = width of the slit
a = 0.000167 m
a = 0.167 mm
So, the width of the slit is 0.167 mm. Hence, this is the required solution.
Answer:
Explanation:
The amplitude is extraneous information for this question.
Period (T) is simply a measure of time (how long it takes to complete a full cycle).
The frequency (f), is the reciprocal (how many cycles it can complete per unit of time).
The frequency reported is 12Hz. Hz is a unit meaning "cycles per second"
Thus 12cycles = 1second.
To find the number of seconds per cycle, simply create the other unit fraction and simplify: