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Naddik [55]
3 years ago
8

What’s bigger kbps or mbps?

Mathematics
2 answers:
leva [86]3 years ago
6 0

KBPS is larger than MBPS.

1 KBPS =  0.001 MBPS

Viefleur [7K]3 years ago
6 0

kbps - kilobytes per second

Mbps - megabytes per second

M - mega is 10⁶ times more

k - kilo is 10³ times more

Therefore 1Mbps is bigger than 1kbps

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How many solutions are possible for a triangle with A = 113° , a = 15, and b = 8
statuscvo [17]

Answer:

One solution.

Step-by-step explanation:

To determine the number of possible solutions for a triangle with A = 113° , a = 15, and b = 8, we're going to use the law of sines which states that: "<em>When we divide side a by the sine of angle A  it is equal to side b divided by the sine of angle B,  and also equal to side c divided by the sine of angle C</em>".

Using the law of sines we have:

\frac{sin(A)}{a} = \frac{sin(B)}{b}

\frac{sin(113)}{15} = \frac{sin(B)}{8}

Solving for B, we have:

sin(B)=0.4909

∠B = 29.4°

Therefore, the measure of the third angle is: ∠C = 37.6°

There is another angle whose sine is 0.4909 which is 180° - 29.4° = 150.6 degrees. Given that the sum of all three angles of any triangle must be equal to 180 deg, we can't have a triangle with angle B=113° and C=150.6°, because B+C>180.

Therefore, there is one triangle that satisfies the conditions.

7 0
3 years ago
5 What is the perimeter? use 3,14
Lera25 [3.4K]

Answer:

I don't understand the instructions, but I'll answer the question in the picture.

The angle next to 52 is vertical to y, so,  90-52=y.

Thus, y=38

6 0
2 years ago
I need help i need to simplify 7(2y+1)+3y
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Simplified form : 17y + 7

5 0
3 years ago
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What is 13 divied it by 2
MrMuchimi

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6.5

Step-by-step explanation:

4 0
2 years ago
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From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
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