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Snezhnost [94]
4 years ago
10

Which pair shares the same empirical formula? C2H4 and C6H6 CH2 and CH4 CH3 and C2H6 CH and C2H4

Chemistry
2 answers:
hoa [83]4 years ago
4 0

Answer:

CH3 and C2H6

Explanation:

guajiro [1.7K]4 years ago
3 0

Answer:

CH₃ and C₂H₆ have same empirical formula.

Explanation:

The empirical formula is the simplest formula obtained by dividing the molecular formula with a number.

It gives the proportion of each element present in the compound however the exact number of each element is shown by only molecular formula.

For CH₃ : the empirical formula will is CH₃

For C₂H₆: the empirical formula will is CH₃ obtained by dividing the molecular formula by two.

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SHOW WORK
stealth61 [152]
PV = nRT —> n = PV/RT

P = 2.90 atm
V = 4.80 L
R = 0.08206 L atm / mol K
T = 62.0 + 273 = 335 K (make sure you convert from celsius to kelvin)

n = (2.90 • 4.80) / (0.08206 • 335) = 0.506 moles of gas
4 0
3 years ago
Write the expression for the equilibrium constant Keq for the reaction below: 2CO(g) + O2(g) ⇔ 2CO2(g) a. [CO2] / [CO] [O2] b. [
kodGreya [7K]

Answer: The answer is NOT A. [CO2] / [CO] [O2]

just took the test and I chose A. The test did not tell me the correct answer. Sorry.

Explanation: NOT, I REPEAT NOT: A. [CO2] / [CO] [O2]

5 0
3 years ago
Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (
aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]

We are given:

\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol

To calculate the number of moles, we use ideal gas equation, which is:

PV=nRT

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = 0.0831\text{ L. bar }mol^{-1}K^{-1}

T = temperature of the mixture = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol

To calculate the heat released of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

\Delta H_{rxn} = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0
3 years ago
An atom contains on proton, one electron, and one neutron. Which two particles are most similar in mass
Darya [45]
Proton and neutron have similar masses.
5 0
4 years ago
Read 2 more answers
Very important !!!!!!!!!!!!
Mademuasel [1]
They speed up reactions by lowering activation energy. Many enzymes change shape when substrates bind.
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3 years ago
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