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Snezhnost [94]
4 years ago
10

Which pair shares the same empirical formula? C2H4 and C6H6 CH2 and CH4 CH3 and C2H6 CH and C2H4

Chemistry
2 answers:
hoa [83]4 years ago
4 0

Answer:

CH3 and C2H6

Explanation:

guajiro [1.7K]4 years ago
3 0

Answer:

CH₃ and C₂H₆ have same empirical formula.

Explanation:

The empirical formula is the simplest formula obtained by dividing the molecular formula with a number.

It gives the proportion of each element present in the compound however the exact number of each element is shown by only molecular formula.

For CH₃ : the empirical formula will is CH₃

For C₂H₆: the empirical formula will is CH₃ obtained by dividing the molecular formula by two.

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Answer:

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Explanation:

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Describe what the isotopes of an element have in common and how are they different.
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Answer:

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Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a
fiasKO [112]

Answer:

                    SEPARATION SCHEME FOR  CATIONS

GIVEN  CATIONS : Ag^{+} \ ,  Fe^{3+} , Cu^{2+}, Ni^{2+}

     

    Step 1:   Add 6mol/dm^3 of HCl to the mixture solution

    Result : This would cause a precipitate of AgCl to be formed

    Reaction :  Ag^{+} _{(aq)} + Cl^{-} _{(aq)}  ---------> AgCl(ppt)

    Step 2 : Next is to remove the precipitate and add H_2S to the remaining          

                 solution in the presence of 0.2 \ mol/dm^3 of HCl

     Result : This would cause a precipitate of CuS to be formed

     Reaction :  Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)

 

     Step 3: Next remove the precipitate then add 6 \ mol/dm^3 of aqueous      

                 NH_3 (NH_3 \cdot H_2 O) , process the solution in a centrifuge,when the  

                 process  is done then sort out the  precipitate from the  solution

                 Now this precipitate is   Fe(OH)_3 and the remaining solution

                contains  (Ni (NH_3)_6)

                 Next take out the precipitate to a different beaker and add HCl

                to it   this will dissolve it, then add a drop of NH_4SCN this will

                form  a precipitate  Fe(SCN)_{6}^{3-} which will have the color of

                 blood  indicating the presence of Fe^{3+}

             

   Reaction :   F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}

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                         Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}

                      Now the remaining mixture contains Ni^{2+}

     

       

Explanation:

6 0
3 years ago
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