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Simora [160]
2 years ago
14

B. Determine the percent composition of each element in NaCl. (1 point) Must show work to

Chemistry
1 answer:
andrey2020 [161]2 years ago
8 0

Answer:

Sodium (Na): (.5 point)

22.99+35.453=58.433.   22.99/58.433=   39%

Chlorine (Cl): (.5 point)

22.99+35.453=58.433.   35.453/58.433= 61%

Explanation:

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astraxan [27]
The most common allotropes are:-
White phosphorus 
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7 0
3 years ago
Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:

  • Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻   (2)

  • Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).  

We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.

In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

Learn more here:

  • brainly.com/question/10547418?referrer=searchResults
  • brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0
2 years ago
What is the reducing agent in the reaction below?
trapecia [35]
Al    is  the  reducing  agent.That    is  answer  B  is  the  above  answer
  Al  acts  as  a  strong  reducing  agent.  It  reduces  crO3  to  form cr  while  Al  is  oxidized  to  Al2O3.    Al is  capable  to  reduce  cr  since  Al  is  higher  in   reactivity  series  than  cr.
8 0
3 years ago
Many industrial reactions, like the reaction of nitrogen gas (N2) and hydrogen gas (H2) to produce ammonia for fertilizers, have
Jobisdone [24]
Catalysts always quicken the experiment
8 0
3 years ago
Which of the following is an acid-base neutralization reaction? (1 point)
GuDViN [60]
It would be NaOH + HCl → <span>NaCl + H2O
</span>
NaOH is sodium hydroxide, which is a strong base. HCl  is hydrochloric acid, which is a strong acid. 

You have a strong base and a strong acid on the left side, however, at the result side, you end up with NaCl + H2O. Sodium chloride is simply table salt and H2O is just water, thus it has been neutralized. 


6 0
3 years ago
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