Answer:
4.7 atm
Explanation:
From the question given above, the following data were obtained:
Total pressure (P) = 15.3 atm
Pressure of Helium, P(He) = 3.2 atm
Pressure of Oxygen, P(O) = 7.4 atm
Pressure of Argon, P(Ar) =?
The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:
P = P(He) + P(O) + P(Ar)
15.3 = 3.2 + 7.4 + P(Ar)
15.3 = 10.6 + P(Ar)
Collect like terms
15.3 – 10.6 = P(Ar)
4.7 = P(Ar)
P(Ar) = 4.7 atm
Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm
Ngl, I really want it! But how do I know you're not scamming?
Answer:
45 °C.
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 1125 J
Mass (M) = 250 g
Final temperature (T₂) = 55 °C
Specific heat capacity (C) = 0.45 J/gºC
Initial temperature (T₁) =?
The initial temperature of the iron can be obtained as illustrated below:
Q = MC(T₂ – T₁)
1125 = 250 × 0.45 (55 – T₁)
1125 = 112.5 (55 – T₁)
Divide both side by 112.5
1125/112.5 = 55 – T₁
10 = 55 – T₁
Collect like terms
10 – 55 = –T₁
–45 = –T₁
Multiply through by –1
45 = T₁
T₁ = 45 °C
Therefore, the initial temperature of the iron is 45 °C
Answer:
condensed matter should be your answer
Explanation:
Answer:
the answer is no.
Explanation:
Basically they move at different speeds because they are not all identical in the earth.
