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3 years ago

Which symbolizes a molecule of a compound?

Chemistry

2 answers:

Phantasy [73]3 years ago

5 0

The answer is A.H202

R u sure

Yerp

Positive?

" ?? Yerp!

saw5 [17]3 years ago

4 0

$H_{2} O_{2}$ symbolizes a molecule of a compound

Answer: Option A

Explanation:

A molecule contains one or more atoms which exists free in nature. It can be monoatomic (single atom), Na, Cu, C, N, H, O, etc. and diatomic (containing 2 atoms), are of two types

Homo-diatomic- same atoms ( $H_{2}, O_{2}, F_{2}, B r_{2}, C l_{2}$ , etc.)
Hetero-diatomic- different atoms (HCl, HF, NO, NaCl, etc.)
Tri-atomic (containing 3 atoms) $\mathrm{H}_{2} \mathrm{O}, \mathrm{N}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}$ , etc.
Polyatomic (containing many atoms) $H_{2} S O_{4}, P_{2} O_{5}, H N O_{3}$ , etc.

A compound consists of more one atom which are chemically combined in a fixed composition. So, here we see $H_{2} O_{2}$ is the molecule which symbolizes a compound since it contains more than one element, H and O present in it.

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List the number of protons, neutrons, and electrons in . B C 6

andrew11 [14]

C 13 has
Protons = 6
neutrons = 6
electrons = 13-6

4 0

3 years ago

How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?

nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

Concentration of the concentrated solution (C₁): 2 M

Volume of the concentrated solution (V₁): ?

Concentration of the diluted solution (C₂): 0.1 M

Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0

3 years ago

How many grams of Fe can be produced when 5.50 g of Fe2O3 reacts?

vichka [17]

Answer:

3,85 g of Fe

Explanation:

1- The first thing to do is calculate the molar mass of the Fe2O3 compound. With the help of a periodic table, the weights of the atoms are searched, and the sum is made:

Molar mass of Fe2O3 = (2 x mass of Fe) + (3 x mass of O) = 2 x 55.88 g + 3 x 15.99 g = 159.65 g / mol

Then, one mole of Fe2O3 has a mass of 159.65 grams.

2- Then, the relationship between the Fe2O3 that will react and the iron to be produced. With the previous calculation, we can say that with one mole of Fe2O3, two moles of Fe can be produced. Passing this relationship to the molar masses, it would be as follows:

1 mole of Fe2O3_____ 2 moles of Fe

159.65 g of Fe2O3_____ 111.76 g of Fe

3- Finally, the calculation of the mass that can be produced of Fe is made, starting from 5.50 g of Fe2O3

159.65 g of Fe2O3 _____ 111.76 g of Fe

5.50 g of Fe2O3 ______ X = 3.85 g of Fe

Calculation: 5.50 g x 111.76 g / 159.65 g = 3.85 g

The answer is that 3.85 g of Fe can be produced when 5.50 g of Fe2O3 react

7 0

2 years ago

Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer: