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3 years ago

Which symbolizes a molecule of a compound?

Chemistry

2 answers:

Phantasy [73]3 years ago

5 0

The answer is A.H202

R u sure

Yerp

Positive?

" ?? Yerp!

saw5 [17]3 years ago

4 0

$H_{2} O_{2}$ symbolizes a molecule of a compound

Answer: Option A

<u>Explanation: </u>

A molecule contains one or more atoms which exists free in nature. It can be monoatomic (single atom), Na, Cu, C, N, H, O, etc. and diatomic (containing 2 atoms), are of two types

Homo-diatomic- same atoms ( $H_{2}, O_{2}, F_{2}, B r_{2}, C l_{2}$ , etc.)
Hetero-diatomic- different atoms (HCl, HF, NO, NaCl, etc.)
Tri-atomic (containing 3 atoms) $\mathrm{H}_{2} \mathrm{O}, \mathrm{N}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{O}$ , etc.
Polyatomic (containing many atoms) $H_{2} S O_{4}, P_{2} O_{5}, H N O_{3}$ , etc.

A compound consists of more one atom which are chemically combined in a fixed composition. So, here we see $H_{2} O_{2}$ is the molecule which symbolizes a compound since it contains more than one element, H and O present in it.

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Energy and Enthalpy Changes, Heat and Work -- Monatomic Ideal Gas dynamically generated plot 2.00-mol of a monatomic ideal gas g

larisa86 [58]

(a) The heat generated in the process is 28 kJ.

(b) The work done in the process is determined as -28 kJ.

<h3>Heat of the isothermal compression </h3>

The heat generated in the process is negative done in the process.

W = -PΔV

W = -P(V₂ - V₁)

W = -P(VB - VA)

W = -11(7 - 12.5)

W = 60.5 L.atm = 60.5 x 101.325 J/L.atm = 6,130.16 J

W = -25(20.5 - 7)

W = -337.5 L.atm = -34,197.18 J

Total work , w = -34,197.18 J + 6,130.16 J = -28 kJ

q = - w

q = 28 kJ

<h3>Change in internal energy</h3>

ΔE = q + w

ΔE = 28 kJ - 28 kJ = 0

Learn more about change in internal energy here: brainly.com/question/17136958

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6 0

2 years ago

Electronegativity is :_______________

bixtya [17]

Answer:

c) the attraction of an atom for the electrons in a covalent bond.

Explanation:

Electronegativity, symbol χ, is a chemical property describing an atom's ability of to attract a shared pair of electrons to itself. It is influenced by the atomic number of the atom and the distance between the valence electrons and the charged nucleus. As the electronegativity number of atoms increases, the more the atom attracts electrons towards itself.

7 0

3 years ago

Read 2 more answers

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:

element: phosphorus sulfur

co9mposition: 39.185% 60.82%

divide with

atomic mass: 39.185/31.0 g/mol 60.82/32.0g/mol

=1.26mol 1.90mol

smallest mole ratio: 1.26mol/1.26mol =1 1.90mol/1.26 mol =1.50

multiply with 2: 2 3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

= $P_4S_6$

8 0

2 years ago

Draw the structures of the major 1,2 and 1,4-products formed by reaction of 1 mole of Br2 with 3-methyl-2,4-hexadiene. Assume th

Marizza181 [45]

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8 0

2 years ago

enzyme‑catalyzed, single‑substrate reaction E + S − ⇀ ↽ − ES ⟶ E + P . The model can be more readily understood when comparing t

laila [671]

Complete Question

The complete question is shown on the first uploaded image

Answer:

[S]<<KM | [S]=KM | [S]>>KM | Not true

____________ | Half of the active | Reaction rate is | Increasing

$[E_{free}]$ is about | sites are filled of | independent of | $[E_{Total}]$ will

equal to $[E_{total}]$ . | | [S] | lower KM

_____________________________________________|____________

[ES] is much | | Almost all active

lower than | | sites are filled

$[E_{free}]$ | |

Explanation:

Generally the combined enzyme $[ES]$ is mathematically represented as

$[ES] = \frac{[E_{total}][S]}{K_M + [S]}----(1)$

for Michaelis-Menten equation

Where $[S]$ is the substrate concentration and $K_M$ is the Michaelis constant

Considering the statement $[S] < < K_M$

Looking at the equation $[S]$ is denominator so it can be ignored(it is far too small compared to $K_M$ ) hence the above equation becomes

$[ES] = \frac{[E_{total}][S]}{K_M}$

Since $[S]$ is less than $K_M$ it means that $\frac{[S]}{K_M} < < 1$

so it means that $[ES] < < [E_{total}]$

What this means is that the number of combined enzymes $[ES]$ i.e the number of occupied site is very small compared to the the total sites $[E_{total}]$ i.e the total enzymes concentration which means that the free sites [ $E_{free}]$ i.e the concentration of free enzymes is almost equal to $[E_{total}]$

Considering the second statement

$[S] = K_M$

So this means that equation one would now become

$[ES] = \frac{[E_{total}][S]}{2[S]} = \frac{[E_{total}]}{2}$

So this means that half of the active sites that is the total enzyme concentration are filled with S

Considering the Third Statement

$[S] >>K_M$

In this case the $K_M$ in the denominator of equation 1 would be neglected and the equation becomes

$[ES] = \frac{[E_{total}] [S]}{[S]} = [E_{total}]$

This means that almost all the sites are occupied with substrate

The rate of this reaction is mathematically defined as

$v =\frac{V_{max}[S]}{K_M [S]}$

Where v is the rate of the reaction(also know as the velocity of the reaction at a given time t) and $V_{max}$ is he maximum velocity of the reaction

In this case also the $K_M$ at the denominator would be neglected as a result of the statement hence the equation becomes

$v = \frac{V_{max}[S]}{[S]} = V_{max}$

So it means that the reaction does not depend on the concentration of substrate [S]

For the final statement(Not True ) it would match with condition that states that increasing $[E_{total}]$ will lower $K_M$

This is because $K_M$ does not depend on enzyme concentration it is a property of a enzyme

7 0

2 years ago