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2 years ago

When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form

Chemistry

1 answer:

DerKrebs [107]2 years ago

4 0

Answer:

18 grams of water

Explanation:

The Balance Chemical Reaction is as follow,

2 NH₄NO₃ → 2 N₂ + O₂ + 4 H₂O

According to Equation,

160 g (2 moles) NH₄NO₃ produces = 72 g (4 moles) of H₂O

So,

40 g of NH₄NO₃ will produce = X g of H₂O

Solving for X,

X = (40 g × 72 g) ÷ 160 g

X = 18 g of H₂O

<em>Hope This Helps!</em>

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three of the following are base units used in the metric system. which is not a base unit? meter liter kilogram gram

Novosadov [1.4K]

The base units used in the metric system are meter for the measurement of distance or displacement, liter as unit measurement of volume, kilogram as a unit of measurement of mass and seconds as unit of measurement of time. The answer is here is D. gram.

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3 years ago

A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?

kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

$density = \frac{250}{173} \\ = 1.4450867052...$

We have the final answer as

Hope this helps you

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3 years ago

What volume of silver metal will mass exactly 1000 grams? The density of silver is 10.5 g/mL.

Mars2501 [29]

To get mL from mass just devide 1000g with 10.5 to get 95.23mL

7 0

3 years ago

A compound is found to have a molar mass of 598 g/mol. if 35.8 mg of the compound is dissolved in enough water to make 175 ml of

TiliK225 [7]

The computation for molarity is:
(x) (0.175 L) = 0.0358 g / 598 g/mol
x = 0.000342093 M
Whereas the osmotic pressure calculation:
pi = iMRT
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K)
pi = 0.0083655 atm
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr
which rounds off to 6.36 torr

7 0

3 years ago

Bromine (63 g) and fluorine (60 g) are mixed to give bromine trifluoride. a) Write a balanced chemical reaction. b) What is the

fiasKO [112]

Answer:

a) Br2 + 3F2 → 2BrF3

<u>b) Br2 is the limiting reactant</u>.

c) There will be formed 86.3 grams of BrF3

d) There will remain <u>0.326 moles of F2 = 12.97 grams</u>

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Explanation:

Step 1: The balanced equation

Br2 + 3F2 → 2BrF3

Step 2: Given data

Mass of Bromine = 63grams

Mass of fluorine = 60 grams

percent yield = 80%

Molar mass of bromine = 79.9 g/mol =

Molar mass of fluorine = 19 g/mol

Molar mass of bromine trifluoride = 136.9 g/mol

Step 3: Calculating moles

Moles Br2 = 63 grams / (2*79.9)

Moles Br2 = 0.394 moles

Moles F2 = 60 grams / (2*19.9)

Moles F2 = 1.508

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

<u>Br2 is the limiting reactant</u>. It will completely be consumed (0394 moles).

There will react 3*0.394 = 1.182 moles of F2

There will remain 1.508 - 1.182 = <u>0.326 moles of F2 = 12.97 grams</u>

Step 5: Calculate moles of BrF3

For 1 mole Br2 consumed, we need 3 moles of F2 to produce 2 moles of BrF3

So there is 2*0.394 moles = 0.788 moles of BrF3 moles produced

Step 6: Calculate mass of BrF3

mass = Moles * Molar mass

mass of BrF3 = 0.788 moles * 136.9 g/mol = 107.88 grams = Theoretical yield

Step 7: Calculate actual yield

% yield = 0.80 = actual yield / theoretical yield

actual yield = 0.80 * 107.88 grams = 86.3 grams

actual yield = <u>86.3 grams</u>

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7 0

3 years ago