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garri49 [273]
3 years ago
9

solve the following and express your answer in the correct number of significant figures 9.11 × 10∧-11 ÷ 6.02 × 10∧23

Chemistry
1 answer:
Greeley [361]3 years ago
8 0
I got 1.513289037E12
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A submicroscopic particle suspended in a solution has a volume 1.3um^3. What is this volume in liters?
k0ka [10]
1000 liters = 1 m^3

and
1.3um^3 = 1.3x10^(-6)m^3

multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3
5 0
3 years ago
Read 2 more answers
What is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?
viktelen [127]

Answer:

4.858 g

Explanation:

Start with the formula

density = \frac{mass}{volume}

density = 1.98 g/mL

volume = 2.45 mL

mass = ??

rearrange the formula to solve for mass

(density) x (volume) = mass

Add in the substitutes and solve for mass

1.98 g/mL x 2.45 mL = 4.858 g

3 0
3 years ago
What is the molarity of 50.84 g of Na2CO3 dissolved in 0.400 L solution?
borishaifa [10]

Answer:

1.20 M

Explanation:

Convert grams of Na₂CO₃ to moles.  (50.84 g)/(105.99 g/mol) = 0.4797 mol

Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M

4 0
3 years ago
Which of the following would increase the strength of an electromagnet? Check all that apply.
TiliK225 [7]

Answer: The correct statements are ; A and B.

Explanation:

The strength of the magnetic field(B) in an electromagnet can be calculated using formula:

B=\mu\frac{N}{L}I

\mu = Relative permeability

N = number of turns

I = Current in the wire of the solenoid

L = length of the solenoid or electromagnetic

As we can see from the formula:

B\propto N

B\propto I

So, by increasing the turns and increasing current flowing through wire one can increase the strength of an electromagnet.

Hence, the correct statements are ; A and B.

5 0
3 years ago
The granular fertilizer 11​-11​-11 is composed of 11​% ​nitrogen, 11​% ​phosphate, and 11​% potassium.​ similarly, the fertilize
Phoenix [80]

The farmer would get 30 lb of 18-16-2 fertilizer.

We can use a variation of the dilution formula to solve this problem.

<em>V</em>₁<em>c</em>₁ + <em>V</em>₂<em>c</em>₂ = <em>V</em>₃c₃

<em>For N </em>

5 lb × 11 + 25 lb × 19 = 30 lb × <em>x</em>

55 + 475 = 30<em>x </em>

<em>x</em> = 530/30 = 18

<em>For PO₄ </em>

5 lb × 11 + 25 lb × 17 = 30 lb × y

55 + 425 = 30<em>y</em>

<em>y</em> = 480/30 = 16

<em>For K </em>

5 lb × 11 + 25 lb × 0 = 30 lb × <em>z </em>

55 + 0 = 30<em>z </em>

<em>x</em> = 55/30 = 2

The farmer would get 30 lb of 18-16-2 fertilizer.

8 0
3 years ago
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