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fenix001 [56]
3 years ago
7

an 80kg mountaineer climbs a 3000m mountain in 10h. What is the average power output during the climb

Physics
1 answer:
inn [45]3 years ago
6 0

Answer:

70 W

Explanation:

Power = work / time

P = mgh / t

P = (80 kg) (9.8 m/s²) (3000 m) / (36000 s)

P = 65.3 W

Rounding to one significant figure, the average power output is 70 W.

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Raindrops fall vertically at 7.5 m/s relative to the Earth. What does an observer in a car moving at 20.2 m/s in a straight line
Vilka [71]

Answer:

vDP = 21.7454 m/s

θ = 200.3693°

Explanation:

Given

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vDP = vDE - vPE     (I)

Substitute in (I) to get that

vDP = - 7.5 j - 20.2 i

The magnitude of vDP is given by

vDP = √((- 7.5)²+(- 20.2)²) m/s =  21.7454 m/s

θ = Arctan (- 7.5/- 20.2) = 20.3693°

θ is in 3rd quadrant so add 180°

θ = 20.3693° + 180° = 200.3693°

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3 years ago
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3 years ago
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