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ziro4ka [17]
2 years ago
7

suppose that you had an ohmmeter and a mystery component that could be either an inductor or a capacitor. How could you use the

ohmmeter to determine what the mystery component was
Physics
1 answer:
sukhopar [10]2 years ago
8 0

Answer:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

Explanation:

To determine the mystery component we will connect the mystery component to a DC voltage source, then I will measure the resistance of the component with the use of Ohmmeter, the value of the resistance of the mystery component will determine what the mystery component is

if the resistance > 1( very high )   then component is a capacitor

if the resistance = 0 then component is an inductor

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Alchen [17]

Answer:(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²

Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m

(a) Angular frequency w= 2πf

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(b) Maximum speed v is given as the product of angular frequency and maximum displacement

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V= 4.06m/s

(c) The maximum acceleration a

= w²x

= (4775.2)² × (0.00085)

a= 19382.15m/s².

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