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erma4kov [3.2K]

2 years ago

14

Which tool(s) are needed to construct a perpendicular bisector of a line segment?

2 answers:

Lynna [10]2 years ago

8 0

I think It’s would be B) A straight edge only.

posledela2 years ago

3 0

Answer: c) a straight edge and a compass

Hope this helps

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Need help pls solve 7x-4y=-7 5x+y=22

aev [14]

<span>7x-4y=-7
5x+y=22

multiply 4 on the 2nd equation
</span>20x+ 4y=88

now you have
7x -4y = -7
20x + 4y = 88
--------------------add
27x = 81
x = 3

7x-4y=-7
7(3)-4y=-7
-4y = -28
y = 7

answer (3, 7) is the solution

3 0

2 years ago

Read 2 more answers

What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve.

lapo4ka [179]

Consider the equation $x^6+6x^3+5=0$ .

First, you can use the substitution $t=x^3$ , then $x^6=(x^3)^2=t^2$ and equation becomes $t^2+6t+5=0$ . This equation is quadratic, so

$D=6^2-4\cdot 5\cdot 1=36-20=16=4^2,\ \sqrt{D}=4,\\ \\ t_{1,2}=\dfrac{-6\pm 4}{2} =-5,-1$ .

Then you can factor this equation:

$(t+5)(t+1)=0$ .

Use the made substitution again:

$(x^3+5)(x^3+1)=0$ .

You have in each brackets the expression like $a^3+b^3$ that is equal to $(a+b)(a^2-ab+b^2)$ . Thus,

$x^3+5=(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25}) ,\\x^3+1=(x+1)(x^2-x+1)$

and the equation is

$(x+\sqrt[3]{5})(x^2-\sqrt[3]{5}x+\sqrt[3]{25})(x+1)(x^2-x+1)=0$ .

Here $x_1=-\sqrt[3]{5} , x_2=-1$ and you can sheck whether quadratic trinomials have real roots:

1. $D_1=(-\sqrt[3]{5}) ^2-4\cdot \sqrt[3]{25}=\sqrt[3]{25} -4\sqrt[3]{25} =-3\sqrt[3]{25}$ .

2. $D_2=(-1)^2-4\cdot 1=1-4=-3$ .

This means that quadratic trinomials don't have real roots.

Answer: $x_1=-\sqrt[3]{5} , x_2=-1$

If you need complex roots, then

$x_{3,4}=\dfrac{\sqrt[3]{5}\pm i\sqrt{3\sqrt[3]{25}}}{2} ,\\ \\x_{5,6}=\dfrac{1\pm i\sqrt{3}}{2}$ .

6 0

3 years ago

Please help and explain so I understand!!

olga_2 [115]

Answer:

x=5

Step-by-step explanation:

$4x^2-11=89$

add 11 to both sides

$4x^2=100$

Divide 4 on both sides

$x^2=25$

Take the square root of both sides to eliminate the power of two from x

$\sqrt{x^2} =\sqrt{25}$

Simplify

$x=5$

8 0

2 years ago

Evaluate and match each expression on the left to its value on the right, when x = 9 and y = 6.

kolezko [41]

Answers: 12-x=3 | x+3y=27 | 4y-10=14 | 1/3xy=18

Explanation: x=9 and y=6
12-(9)=3 | (9)+3(6)=27 | 4(6)-10=14 | 1/3(9)(6)=18

5 0

2 years ago

Brandon buys a radio for $46.49 in a state where the sales tax is 7%.

zysi [14]

Answer:

Brandon pays $49.74 in total

Step-by-step explanation:

$46.49 x 1.07 = $49.74

8 0

3 years ago