1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
7

In an experiment, an object is heated.

Physics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

B) 300 J/°C

Explanation:

Q = 3kJ = 3000J

ΔT = 10°C

3000J/10°C = 300J/°C

You might be interested in
g what are the bands of electromagneitc radiation and how are they related to energy frequency and wavelength
ch4aika [34]

Answer:

The details of bands is given in explanation.

Explanation:

The electromagnetic waves are differentiated into different bands based upon their wavelengths and frequencies. The names of different bands are as follows:

1. Radio Waves

2. Micro Waves

3. Infra-red

4. Visible light

5. Ultra Violet

6. X-rays

7. Gamma Rays

<u>The frequency of every region or rays increases from 1 through 7</u>. The <u>energy of rays also increase from 1 through 7</u>. Since, the wave length is inversely related to energy and frequency, thus the <u>wavelength of rays decrease from 1 through 7</u>.

A detailed information of the bands is provided in the picture attached.

3 0
3 years ago
What is the advantage of constantly performing endurance training such as Brisk walking or jogging, Yard work, Dancing, Swimming
Eduardwww [97]
Exercise or Getting grader Stomata
5 0
2 years ago
A cyclist rides at 6.20 m/s through a intersection. A stationary car begins to
Xelga [282]

Answer:

The width of the intersection is 20 meters

Explanation:

The speed with which the cyclist is riding, v₁ = 6.20 m/s

The rate at which the car starts to accelerate, a = 3.844 m/s²

The initial velocity of the car = The car is stationary at the start = 0 m/s

The time at which the cyclist and the car reach the other side of the intersection = The same time;

Let 't' represent the time at which the cyclist and the car both reach the other side of the intersection, we have;

The distance travelled by the cyclist = The distance traveled by the car

∴ v₁ × t = 1/2 × a × t²

Plugging in the values for 'v₁', and 'a' in the above equation, we get;

6.20 × t = 1/2 × 3.844 × t²

∴ 1.922·t² - 6.20·t = 0

∴ t·(1.922·t - 6.20) = 0

t = 0, or t = 6.20/1.922 = 100/31

The time at which the cyclist and the car both reach the other side of the intersection, t = 100/31 seconds

The with of the intersection, w = v₁ × t

∴ w = 6.20 × 100/31 = 100/5 = 20

The width of the intersection, w = 20 meters.

8 0
3 years ago
A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the sout
Morgarella [4.7K]

Answer: The taxi is moving with reference to A) Monument Circle. For each leg of the trip, the taxi's A) Average speed stays the same, but it's B) Average velocity changes.

Explanation: Brainliest Please!!!!

7 0
3 years ago
The suspension system of a 1700 kg automobile "sags" 7.7 cm when the chassis is placed on it. Also, the oscillation amplitude de
spin [16.1K]

Answer:

the spring constant k = 5.409*10^4 \ N/m

the value for the damping constant \\ \\b = 1.518 *10^3 \ kg/s

Explanation:

From Hooke's Law

F = kx\\\\k =\frac{F}{x}\\\\where \ F = mg\\\\k = \frac{mg}{x}\\\\given \ that:\\\\mass \ of \ each \ wheel = 425 \ kg\\\\x = 7.7cm = 0.077 m\\\\g = 9.8 \ m/s^2\\\\Then;\\\\k = \frac{425 \ kg * 9.8 \ m/s^2}{0.077 \ m}\\\\k = 5.409*10^4 \ N/m

Thus; the spring constant k = 5.409*10^4 \ N/m

The amplitude is decreasing 37% during one period of the motion

e^{\frac{-bT}{2m}}= \frac{37}{100}\\\\e^{\frac{-bT}{2m}}= 0.37\\\\\frac{-bT}{2m} = In(0.37)\\\\\frac{-bT}{2m} = -0.9943\\\\b = \frac{2m(0.9943)}{T}\\\\b = \frac{2m(0.9943)}{\frac{2 \pi}{\omega}}\\\\b = \frac{m(0.9943) \ ( \omega) )}{ \pi}

b = \frac{m(0.9943)(\sqrt{\frac{k}{m})}}{\pi}\\\\b = \frac{425*(0.9943)(\sqrt{\frac{5.409*10^4}{425}) }    }{3.14}\\\\b = 1518.24 \ kg/s\\\\b = 1.518 *10^3 \ kg/s

Therefore; the value for the damping constant \\ \\b = 1.518 *10^3 \ kg/s

5 0
3 years ago
Other questions:
  • The magnetic dipole moment of Earth is 8.00 ✕ 1022 J/T. Assume that this is produced by charges flowing in Earth's molten outer
    5·1 answer
  • Estimate the acceleration you subject yourself to if you walk into a brick wall at normal walking speed. (Make a reasonable esti
    7·1 answer
  • How high is the average telephone pole
    9·2 answers
  • A large box of mass M is moving on a horizontal surface at speed v0. A small box of mass m sits on top of the large box. The coe
    13·1 answer
  • Now that you are familiar with MRI's, nanotechnology and micro-bots, use your imagination to brainstorm other probable invention
    9·1 answer
  • Hii please help i’ll give brainliest if you give a correct answer please please hurry
    7·1 answer
  • Which of the following statements is false?
    9·1 answer
  • ¿Es posible determinar el valos de las variables que intervienen en los diferentes movimientos en dos dimensiones?
    6·1 answer
  • Select the correct answer.
    8·2 answers
  • Which element accumulates in the environment due to the use of
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!