According to the plot, the positions at time <em>t</em> = 0 s and <em>t</em> = 19 s are -1 m and -2 m, respectively. So the average velocity for the 19-s interval is
Answer:
V₂=4.57 x 10³ L
Explanation:
Given that
V₁= 2.88 x 10³ L
P₁=722 mm Hg
T₁ = 19°C
T₁ =292 K
P₂=339 mm Hg
T₂= - 55°C
T₂=218 K
Lets take final volume = V₂
We know that ideal gas equation
PV = m R T
By applying mass conservation
V₂=4.57 x 10³ L
Therefore volume will be 4.57 x 10³ L
Answer:
0.09 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
From the question, expression for acceleration is given as
F' = ma
Using Pythagoras Theory,
√(F₁²+F₂²) = ma................... Equation 1
Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.
make a the subject of the equation
a = √(F₁²+F₂²) /m................ Equation 2
Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,
Substitute into equation 2
a = [√(64²+38²)]/825
a = {√(5540)}/825
a = 74.43/825
a = 0.09 m/s²
