A = (Vf-Vi) / t,
a = (6-0)/3 = 2m/s^2,
F = ma = 2 * 2 = 4N
Answer:
option A is correct because air friction is greater than gravity
Explanation:
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Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm
Answer:
5 L
Explanation:
Ideal gas law:
PV = nRT
If P, n, and R are constant, then:
n₁R/P₁ = n₂R/P₂
Using ideal gas law, we can rewrite this as:
V₁/T₁ = V₂/T₂
This is known as Charles' law.
Plugging in values:
10 L / 546 K = V / 273 K
V = 5 L
