█ Question <span>█
</span><span>In an electronic transition, an atom cannot emit what?
</span>█ Answer █
When an electronic transition is occurring, an atom cannot emit ultra-violet light.
<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia</span></span>
Answer:
P(bat) = V²r/(R+r)²
Explanation:
Let the resistance of the coil be R
Internal resistance of the battery be r
Emf of the battery = V
Power dissipated in the internal resistance of the battery is normally given as P = I²r
where I is the current flowing in the circuit.
From Ohm's law,
V = I R(eq)
R(eq) = (R + r)
I = V/(R+r)
P = I²r
P = [V/(R+r)]²r
P = V²r/(R+r)²
Hope this Helps!!!
' C ' is the only correct statement on the list. We don't know anything about diagram-x or diagram-y because we can't see them.
Momentum = mass x velocity
12 = 4 x v | ÷ both sides by 4
12 ÷ 4 =v
v= 3 m/s
the answer is a) 0.00235 because 1/425=0.00235. hope I helped!