Answer:
12
N
in the direction opposite to electric field.
Explanation:
Force on a charged particle
q
due to electric field
E
is given by
→
F
=
q
→
E
|
F
|
=
−
0.06
C
×
200
N
C
=
−
12 N
Here negative indicates that force is in the direction opposite to electric field.
Answer:
The answer to your question is below
Explanation:
Data 1
mass 1 = 250
mass 2 = 250 kg
gravity constant = 6.67 x 10⁻¹¹ Nm²/kg²
distance = 8 m
Formula
Substitution
Result
F = 0.000000065 N
Data 2
mass 1 = 1000 kg
mass 2 = 1000 kg
distance = 5 m
Substitution
Result
F = 0.000002667 N
Answer:
Alpha = ω^2 R where R is radius of blade
g = w^2 r where r is distance from center
ω^2 R = 11.5 ω^2 r
R / r = 11.5 / 9.8 = 1.17
Or r = .852 R
Since the angular acceleration depends on both R and ω it seems that one can only get r as it depends on R
Answer:
Resistance of the second wire is twice the first wire.
Explanation:
Let us first see the formula of resistance;
R = pxL/A
Here L is the lenght of the wire, A the area and p is the resistivity of wire.
As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.
Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law
I = V/R
Answer:
The direction of the car’s change in linear momentum is 149.04° West of North
Explanation:
Momentum is defined as the product of mass of a body and its velocity
Momentum = mass × velocity
Change in Momentum = mass × change in velocity
∆P = m∆v
∆P = m(v-u)
Given m = 1500kg
v = 25m/s
u = 15m/s
∆P = 1500(25-15)
∆P = 1500×10
∆P = 15,000kgm/s
Since the car first travels due East i.e +x direction
x = 25m/s
Travelling due south is negative y direction
y = -15m/s
Direction of the car change
θ = tan^-1(y/x)
θ = tan^-1(-15/25)
θ = tan^-1(-0.6)
θ = -30.96°
Since tan is negative in the second quadrant
θ = 180-30.96
θ = 149.04°
The direction of the car’s change in linear momentum is 149.04° West of North
