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3 years ago

11

I need to identify the parts of a wave

1 answer:

Zina [86]3 years ago

8 0

Answer: A: Amplitude B: Trough C: Wavelength D: Crest

Explanation:

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In an experiment, an object is heated.

mariarad [96]

Answer:

B) 300 J/°C

Explanation:

Q = 3kJ = 3000J

ΔT = 10°C

3000J/10°C = 300J/°C

6 0

2 years ago

What causes earth to have a complete year

RUDIKE [14]

Answer:

Earth's Tilt and The Seasons. Earth, like all of the planets in the Solar System, travels around the Sun. One complete orbit of the Sun is known as a year and it takes Earth 365 days, 5 hours, 48 minutes and 46 seconds to complete an orbit. The changing seasons are caused by the fact that Earth is tilted. please vote me brainliest i can't message no one cuz i haven't got enough points i'm desperate.

Explanation:

7 0

3 years ago

A 10 kg ball is held above a building with a height of 30 m. What is the

Darina [25.2K]

Answer: 2940 J

Explanation: solution attached:

PE= mgh

Substitute the values:

PE= 10kg x 9.8 m/s² x 30 m

= 2940 J

6 0

3 years ago

As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p

coldgirl [10]

Answer:

Explanation:

charge, q = 1.6 x 10^-19 C

distance, r = 911 nm = 911 x 10^-9 m

The Coulomb's force is given by

$F=\frac{Kq_{1}q_{2}}{r^{2}}$

$F=\frac{9\times 10^{9}\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{\left (911\times 10^{-9} \right )^2}$

F = 2.78 x 10^-16 N

The force between the electron and the proton is 2.78 x 10^-16 N.

4 0

2 years ago

When the starter motor on a car is engaged, there is a 310 A current in the wires between the battery and the motor. Suppose the

Blababa [14]

Answer:

Diameter will be 351.42 mm

Explanation:

We have given current flowing in the copper wire i = 310 A

Voltage drop across the wire V = 0.55 volt

We know that resistance is given by $R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega$

Length of the copper wire l = 1 m

Resisitivity of the copper wire $\rho =1.72\times 10^{-8}\Omega m$

We know that resistance $R=\frac{\rho l}{A}$

$0.00177=\frac{1.72\times 10^{-8}\times 1}{A}$

$A=969.4545\times 10^{-8}m^2$

As area $A=\pi r^2$

$3.14\times r^2=969.4545\times 10^{-8}$

$r=17.57\times 10^{-4}m$

So diameter $d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m$ = 351.42 mm

3 0

3 years ago