Answer : The partial pressure of B in the container is, 25.94 atm
Explanation : Given,
Total pressure = 38.9 atm
The given chemical reaction is:
Initial pressure p 0 0
At eqm. 0 2p p
The total pressure expression will be:
Total pressure = 2p + p
38.9 atm = 2p + p
38.9 atm = 3p
p = 12.97 atm
Now we have to calculate the partial pressure of B in the container.
The partial pressure of B in the container = 2p = 2(12.97) = 25.94 atm
Thus, the partial pressure of B in the container is, 25.94 atm
Answer:
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Answer:
- Density Liquid = 0.841 g/mL
- Density Metal = 2.711 g/cm³
Explanation:
- The density of the liquid is:
Mass Liquid / Volume Liquid
From the problem we know that Volume Liquid = 25.0 mL, <u>the mass of the liquid can be calculated by substracting masses</u>:
- Mass Liquid + Mass Slug + Mass Empty Cylinder = 125.934 g
- Mass Liquid + 15.454 g + 89.450 g = 125.934 g
- Mass Liquid = 125.934 g - 15.454 g - 89.450 g
Thus the density of the liquid is:
Density Liquid = 21.030 g / 25.0 mL = 0.841 g/mL
2. The density of the metal slug is:
Mass Metal / Volume Metal
We already know that the mass of the slug is 15.454 g. Its volume can be calculated using <em>Archimede's principle</em>, which states that the volume of an object is equal to the volume of liquid it displaces, in other words:
Volume Metal = 30.7 mL - 25.0 mL = 5.7 mL
Thus the density of the metal slug is
Density Metal = 15.454 g / 5.7 mL = 2.711 g/mL = 2.711 g/cm³
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