All categories

3 years ago

The reproductive organs of the male

Chemistry

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Male reproductive organs: testes
Female reproductive organs: ovaries
Ovaries produce: eggs
The testes produce: sperm

gtnhenbr [62]3 years ago

4 0

Answer:The reproductive organs of the male: Testes

The reproductive organs of the female are the: ovaries

The ovaries produce the: Eggs

The testes produce the: Sperm

You might be interested in

If an instrument has 10 ml td +/- 0.01 ml written on it, the user should ..... question 5 options: record 10 ml in the notebook

galina1969 [7]

Answer : The correct option is "record 10.00 ml in the notebook after using it."

Explanation :

If an instrument has "10 mL TD" written on it, that means the instrument is meant To Deliver (TD) 10 mL of volume.

Therefore the option that has 5.00 mL is not correct.

"+/- 0.01 mL" indicates the precision of the instrument. We know that no measurement is 100% accurate and there is always some uncertainty associated with any measurement.

Here, 0.01 indicates the uncertainty in the measurement.

When we have 0.01 mL , that means the instrument can record precisely to the hundredths place.

The more the significant figures, the greater is the accuracy of the measurement.

Therefore when we use an instrument that has "+/- 0.01 mL" written on it, we should record the reading as 10.00 mL

6 0

3 years ago

The universe is estimated to be how old?

bonufazy [111]

Its D. 13-14 billion years

7 0

3 years ago

Read 2 more answers

Nuclear energy is associated with

maria [59]

Protons and neutrons

6 0

3 years ago

Read 2 more answers

Consider the reaction: CO2(g) + CCl4(g) ⇌ 2 COCl2(g) ΔG° = 46.9 kJ Under the following conditions at 25 oC: LaTeX: P_{CO_2}P C O

Mamont248 [21]

Answer : The value of $\Delta G_{rxn}$ is, $-47.0kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln K_p$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy = 46.9 kJ

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

$K_p$ = equilibrium constant

First we have to calculate the value of $K_p$ .

The given balanced chemical reaction is,

$CO_2(g)+CCl_4(g)\rightarrow 2COCl_2(g)$

The expression for reaction quotient will be :

$K_p=\frac{(p_{COCl_2})^2}{(p_{CO_2})\times (p_{CCl_4})}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$K_p=\frac{(0.653)^2}{(0.459)\times (0.984)}$

$K_p=0.944$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln K_p$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-46.9kJ/mol+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (0.944)$

$\Delta G_{rxn}=-47.0kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is, $-47.0kJ/mole$

3 0

3 years ago

What do Lewis dot structures show?

inessss [21]

Answer:

They display the number of valence electrons surrounding an element or compound.

Explanation:

8 0

3 years ago