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3 years ago

5

A stone is dropped from the top of a cliff. the splash it makes when striking the water below is heard 3.5 s later. the speed of

sound in air is 343 m/s.

1 answer:

Margaret [11]3 years ago

4 0

The answer would be 55

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baherus [9]

$\huge\underline\mathtt\colorbox{cyan}{G=}$

$6.673 \times {10}^{ - 11}$

And unit is Nm^2/kg^2

8 0

2 years ago

Read 2 more answers

Which of the following is an example of sound energy

dedylja [7]

Sound energy is produced when an object vibrates so an example would be a telephone ringing or someone playing a bass guitar

4 0

3 years ago

Examine the scenario. Object A has 5 protons and 5 electrons. Object B has 5 protons and 7 electrons. Which option most accurate

Travka [436]

<span>Last choice on the list:
Object A has a net charge of 0 because the positive and negative
charges are balanced.
Object B has a net charge of –2 because there is an imbalance of
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4 0

3 years ago

If a 54 kg sprinter can accelerate from a standing start to a speed of 10 m/s in 3 s, what average power is generated?

lora16 [44]

Answer:

Power, P = 600 watts

Explanation:

It is given that,

Mass of sprinter, m = 54 kg

Speed, v = 10 m/s

Time taken, t = 3 s

We need to find the average power generated. The work done divided by time taken is called power generated by the sprinter i.e.

$P=\dfrac{W}{t}$

Work done is equal to the change in kinetic energy of the sprinter.

$P=\dfrac{\dfrac{1}{2}mv^2}{t}$

$P=\dfrac{\dfrac{1}{2}\times 54\ kg\times (10\ m/s)^2}{3\ s}$

P = 900 watts

So, the average power generated by the sprinter is 900 watts. Hence, this is the required solution.

3 0

3 years ago

RP 1 - Specific Heat Capacity GCSE Exam Questions (B.S.G)

Stels [109]

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

A sample of 0.50 kg of water boils (reaches 100 °C). After a while, its temperature decreases by 22 °C.

We can calculate the energy transferred to the surroundings from the water in the form of heat (Q) using the following expression.

$Q = c \times m \times \Delta T = \frac{4200J}{kg.\° C} \times 0.50kg \times (-22\° C) \times \frac{1kJ}{1000J} = -46.2 kJ$

where,

c: specific heat capacity of water
m: mass of water
ΔT: change in the temperature

When the temperature of 0.50 kg of water decreases by 22 °C, the energy transferred to the surroundings from the water is -46.2 kJ.

Learn more: brainly.com/question/16104165

8 0

3 years ago