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Aliun [14]
2 years ago
15

20" id="TexFormula1" title="\huge\bold{\purple{\bold{⚡Gravitational Constant?⚡}}} " alt="\huge\bold{\purple{\bold{⚡Gravitational Constant?⚡}}} " align="absmiddle" class="latex-formula"> ​
Physics
2 answers:
baherus [9]2 years ago
8 0

\huge\underline\mathtt\colorbox{cyan}{G=}

6.673 \times  {10}^{ - 11}

And unit is Nm^2/kg^2

crimeas [40]2 years ago
6 0

Explanation:

The attractive force between two bodies when multiplied by the product of the masses of two bodies and divided by the square of the distance between them.

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The magnification is less than 1 what does it mean​
igomit [66]
If magnification is less than one it means the image is the same exact size as the object.
4 0
2 years ago
Tres litros de oxigeno gaseoso a 15 grados centígrados y a presión atmosférica (1atm), se lleva a una presión de 10mm de Hg. ¿ c
lana [24]

Answer:

Three liters of gaseous oxygen at 15 degrees Celsius and at atmospheric pressure (1atm), is brought to a pressure of 10mm Hg. What will be the volume of the gas now if the temperature has not changed?

Explanation:

Given that, the temperature is constant

Then, using gay Lussac law

P1•V1 / T1 = P2•V2 / T2

Since temperature is constant

Then, T1 = T2 = T and they cancels out

So, we are left with

P1•V1 = P2•V2

Given that, .

Initial volume

V1 = 3 litres.

Initial pressure

P1 = 1atm = 101325 Pa

Final pressure

P2 = 10mmHg = 1333.22 Pa

Then, we want to find the final volume V2

Make V2 subject of formula.

V2 = V1•P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litres

So, the final volume is 288 litres.

In Spanish

Dado que la temperatura es constante

Luego, usando la ley gay de Lussac

P1 • V1 / T1 = P2 • V2 / T2

Como la temperatura es constante

Entonces, T1 = T2 = T y se cancelan

Entonces, nos quedamos con

P1 • V1 = P2 • V2

Dado que, .

Volumen inicial

V1 = 3 litros.

Presión inicial

P1 = 1atm = 101325 Pa

Presión final

P2 = 10 mmHg = 1333.22 Pa

Entonces, queremos encontrar el volumen final V2

Hacer V2 sujeto de fórmula.

V2 = V1 • P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litros

Entonces, el volumen final es de 288 litros

8 0
3 years ago
What types of collisions can result from making unsafe passes?
SSSSS [86.1K]
<span>Unsafe passes are passes with restricted line of sight, passes with cross traffic, narrow passes which are unsafe. 
Several collision can result from making unsafe passes. Some of them are: 
-getting run off the road
-getting sideswiped
-getting hit head-on</span>
7 0
3 years ago
A person travels by car from one city to another with differem constan1 speeds between pairs of cities. She drives for 30.0 min
Montano1993 [528]

Answer:

a.52.9 km/h

b.90 km

Explanation:

We are given that

v_1=89km/h

t_1=30min

v_2=100km/h

t_2=12min

v_3=40km/h

t_3=45 min

Time spend on eating lunch and buying ga=15 min.

a.Total time=30+12+45+15=102 minute=\frac{102}{60}=1.7 hour

1 hour=60 minutes

Distance=speed\times time

d_1=v_1\times t_1=80\times\frac{30}{60}=40km

d_2=100\times \frac{12}{60}=20 km

d_3=40\times \frac{45}{60}=30 km

Total distance=d_1+d_2+d_3=40+20+30=90km

Average speed=\frac{total\;speed}{total\;time}

Using the formula

Average speed=\frac{90}{1.7}=52.9Km/h

b.Total distance between the initial and final city lies along the route=90 km

4 0
3 years ago
A circular coil of wire having a diameter of 20.0 cm and 3000 turns is placed in the earth's magnetic field with the normal of t
Bess [88]

Explanation :

It is given that,

Diameter of the coil, d = 20 cm = 0.2 m

Radius of the coil, r = 0.1 m

Number of turns, N = 3000

Induced EMF, \epsilon=1.5\ V

Magnitude of Earth's field, B=10^{-4}\ T

We need to find the angular frequency with which it is rotated. The induced emf due to rotation is given by :

\epsilon=NBA\omega

\omega=\dfrac{\epsilon}{NBA}

\omega=\dfrac{1.5}{3000\times 10^{-4}\times \pi (0.1)^2}

\omega=159.15\ rad/s

So, the angular frequency with which the loop is rotated is 159.15 rad/s. Hence, this is the required solution.

3 0
2 years ago
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