<img src="https://tex.z-dn.net/?f=%5Chuge%5Cbold%7B%5Cpurple%7B%5Cbold%7B%E2%9A%A1Gravitational%20Constant%3F%E2%9A%A1%7D%7D%7D%

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3 years ago

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Physics

2 answers:

baherus [9]3 years ago

8 0

$\huge\underline\mathtt\colorbox{cyan}{G=}$

$6.673 \times {10}^{ - 11}$

And unit is Nm^2/kg^2

crimeas [40]3 years ago

6 0

Explanation:

The attractive force between two bodies when multiplied by the product of the masses of two bodies and divided by the square of the distance between them.

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A 2.5 gram penny and a 1 gram paper clip are dropped from the Empire State Building.

frutty [35]

Answer:

According to Newton's second law of motion, the force $F$ exerted on an object is directly proportional to its mass $m$ and acceleration $a$ :

$F=m.a$ (1)

In the case of this two objects with different masses the force will be the weight $W$ , the force with which the objects are atracted to the Earth center due gavity $g$ :

$W=m.g$ (2)

This means we wil have two weights in this particular situation, where the weight of the penny is greater than the weight of the paper clip.

Nevertheless, we have another situation here:

When objects are dropped from a certain height and fall to the ground with the acceleration due gravity $g$ (in this case we are on Earth, so the gravity value is $9.8\frac{m}{s^{2}}$ ) is called free fall.

According to the experiments, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is the acceleration of gravity. This means these objects experience the acceleration of gravity regardless of their mass and therefore their weight.

For example, if we have two objects with different masses, the penny and the paper clip; where the first object is greater than the second; both will fall to the ground at the same time with the same gravity acceleration.

Now, in the real life we have air on Earth, and may have air resistance. In this case the greater object (the penny) will fall to the ground before the lesser object (the paper clip), because the paper clip was more affected by air resistance than the penny.

However, if the air resistance is too small that we can approximate it to zero in the calculations, in free fall the objects will accelerate downwards at $9.8\frac{m}{s^{2}}$ and hit the ground at approximately the same time.

7 0

4 years ago

All of the following are contributions of the Space Center for Florida except which one?

Anna007 [38]

Answer:

You have to give us an answer choice : )

4 0

3 years ago

Read 2 more answers

1)Atmospheric decreases with the increase with in height?

lina2011 [118]

Answer:

Explanation:

pressure decreases with increasing altitude. The pressure at any level in the atmosphere may be interpreted as the total weight of the air above a unit area at any elevation. At higher elevations, there are fewer air molecules above a given surface than a similar surface at lower levels.

5 0

3 years ago

how long would it take a 3.4 kg bike with 79 kg rider traveling at 18.6 m/s to stop if 867 N of force is applied to the brakes?

nalin [4]

Answer: 1.76 s

Explanation:

We have the following data:

$m=3.4 kg+79 kg=82.4 kg$ is the total mass of the bike and the rider

$V_{o}=18.6 m/s$ is the initial velocity

$F=867 N$ is the force applied to the brakes

Firstly, we will find the acceleration $a$ with the following equation:

$F=m.a$ (1)

Isolating $a$ :

$a=\frac{F}{m}$ (2)

$a=\frac{867 N}{82.4 kg}$ (3)

$a=10.52 m/s^{2}$ (4) This is the magnitude of the acceleration, however, since the final velocity is 0 m/s, this means the direction is negative

Hence:

$a=-10.52 m/s^{2}$ (5)

On the other hand, with the following equation we can find the time $t$ :

$V=V_{o}+at$ (6)

Where:

$V=0 m/s$ is the final velocity (the bike stops)

Isolating $t$ :

$t=-\frac{V_{o}}{a}$ (7)

$t=-\frac{18.6 m/s}{-10.52 m/s^{2}}$ (8)

Finally:

$t=1.76 s$ This iste time it takes to the bike to stop

7 0

3 years ago

I need help, please answer

Burka [1]

This being a perfect collision means no energy is lost during the collision. Because this question asks for speed and not velocity, the speed will be the same because the final energy is the same. The speed after the collision would therefore be 1.27 m/s.

7 0

4 years ago