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arlik [135]
3 years ago
11

A small ferryboat is 4.70 m wide and 6.10 m long. When a loaded truck pulls onto it, the boat sinks an additional 5.00 cm into t

he river. What is the weight of the truck
Physics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

   M = 1433.5 kg

Explanation:

This exercise is solved using the Archimedean principle, which states that the hydrostatic thrust is equal to the weight of the desalinated liquid,

              B = ρ g V

with the weight of the truck it is in equilibrium with the push, we use Newton's equilibrium condition

           Σ F = 0

           B-W = 0

           B = W

       body weight

           W = M g

the volume is

           V = l to h

           rho_liquid g (l to h) = M g

           M = rho_liquid l a h

           

we calculate

            M = 1000 4.7 6.10 0.05

           M = 1433.5 kg

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Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

                                          v = d/t

∴                                         t = d/v

Substituting in the above values in the given equation

                                           t = 88/28

                                            = 3.142 s

The acceleration is given by the formula

                                         a = (v-u)/t

                                            = (0 - 28)/3.142

                                            = -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

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2 years ago
An engineer wants to double the water supply reserve and makes a tank 1.26 times as big as the old one in linear dimension, and
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Now, the engineer makes a tank 1.26 times as big in heigh and 1.41 times as large with respect to diameter, then the new volume of this tank will be:

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V_{new}=1.41^2*1.26\pi (\frac{D}{2})^{2}h

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I hope it helps you!

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