Answer:
Archaeologist use radioactive isotopes to determine the ages of various objects, rocks and materials. This is called radioactive dating. Radioactive isotope Carbon-14 is widely used for this dating process.
Scientists use radioactive isotopes in agriculture to monitor or study the uptake and use of essential nutrients by plants from the soil. This helps to determine viability, productivity and nutritious ability of the plants on a piece of land.
Geologists use radioactive isotopes to trace leaks in underground water storage, pipes. Radioactive isotopes are effective tracers because their radioactivity can be easily detected.
Answer:
A. α = - 1.047 rad/s²
B. θ = 14.1 rad
C. θ = 2.24 rev
Explanation:
A.
We can use the first equation of motion to find the acceleration:
where,
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s
t = time = 3 s
α = angular acceleration = ?
Therefore,
<u>α = - 1.047 rad/s²</u>
B.
We can use the second equation of motion to find the angular distance:
<u>θ = 14.1 rad</u>
C.
θ = (14.1 rad)(1 rev/2π rad)
<u>θ = 2.24 rev</u>
Answer:
Material that was produced by or was/is part of living organism
Explanation:
- organic is defined as the natural matter or compounds with a carbon base, and also refers to food and meat grown or raised without chemicals or pesticides.
-Natural plant matter is an example of something that would be described as organic.
Answer
The second rock will land 2.4s after the first rock
Explanation:
Given that
Height of the building s=50m
We assume that the first rock is acting with gravity so that a=9.81m/s
And initial velocity u=0
Applying the equation of motion
S=ut+1/2at²
50=0*t+1/2(9.81)t²
50=4.905t²
t²=50/4.905
t²=10.19
t=√10.19
t=3.19sec
For the second rock initial velocity u=8m/s and v=0 and a=9.81
Applying the equation of motion
v=u+at
0=8+9.81t
t=-8/9.81
t=0.81sec
Hence the second rock will land 2.4s after the first rock
I.e
3.19-0.81
Acceleration = final velocity - initial velocity/time taken
A = Vf-Vi/t
A = 1 m/s - 0 m/s / 4 sec
A = 1 m/s / 4 sec
A = 0.25 m/s2
