A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a
force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.
1 answer:
Answer:
Mass, m = 0.49 kg
Explanation:
It is given that,
A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.
We need to find the mass of the ice.
On a sloping surface, the force with which it strikes is given by :

So, the mass of the ice block is 0.49 kg.
You might be interested in
Answer:
As a result, light travels fastest in empty space, and travels slowest in solids. In glass, for example, light travels about 197,000 km/s.
Explanation:
Answer:
4.2 m/s
Explanation:
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(35 g) (9 m/s) + (75 g) (-7 m/s) = (35 g) (-15 m/s) + (75 g) v
315 g m/s − 525 g m/s = -525 g m/s + (75 g) v
315 g m/s = (75 g) v
v = 4.2 m/s
Answer:
rate of change
Explanation:
The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.
Explanation:
Given: 


The work function
is then

