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2 years ago

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A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a

force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.

1 answer:

laiz [17]2 years ago

8 0

Answer:

Mass, m = 0.49 kg

Explanation:

It is given that,

A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.

We need to find the mass of the ice.

On a sloping surface, the force with which it strikes is given by :

$F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg$

So, the mass of the ice block is 0.49 kg.

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Complete Question

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Answer:

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Explanation:

From the question we are told that

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Substituting values

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