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3 years ago

What is ancient japan remembered for

Chemistry

1 answer:

Katarina [22]3 years ago

3 0

Hi!

The Samurai is what I would attribute to the memory of Ancient<span> Japan.</span>

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What volume of hydrogen will be produced at STP by the reaction of 78.33 g of aluminum with excess water

nydimaria [60]

The balanced equation for the above reaction is
2Al + 6H₂O ---> 2Al(OH)₃ + 3H₂
stoichiometry of Al to H₂ is 2:3
number of Al moles reacted - 78.33 g / 27 g/mol = 2.901 mol
according to molar ratio
2 mol of Al forms - 3 mol of H₂
therefore 2.901 mol of Al - forms 3/2 x 2.901 = 4.352 mol

molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP
if 1 mol occupies 22.4 L
then 4.352 mol occupies - 22.4 L/mol x 4.352 mol = 97.48 L
volume occupied by H₂ is 97.48 L

4 0

3 years ago

An element, X, can form a chloride (XCl3) and an iodide (XI3). The chloride can be converted quantitatively into the iodide when

Arlecino [84]

Answer : The chemical symbol for this element is, (La)

Explanation : Given,

Mass of $XCl_3$ = 0.760 g

Mass of $XI_3$ = 1.610 g

The given chemical reaction is:

$2XCl_3+3I_2\rightarrow 2XI_3+3Cl_2$

First we have to calculate the moles of $XCl_3$ and $XI_3$ .

$\text{Moles of }XCl_3=\frac{\text{Mass of }XCl_3}{\text{Molar mass of }XCl_3}$

Molar mass of Cl = 35.5 g/mole

Let the molar mass of element 'X' be, M

$\text{Moles of }XCl_3=\frac{0.760}{[M+3(35.5)]}$

and,

$\text{Moles of }XI_3=\frac{\text{Mass of }XI_3}{\text{Molar mass of }XI_3}$

Molar mass of I = 126.9 g/mole

Let the molar mass of element 'X' be, M

$\text{Moles of }XI_3=\frac{1.610}{[M+3(126.9)]}$

From the balanced chemical reaction we conclude that,

The moles of ratio of $XCl_3$ and $XI_3$ is, 1 : 1

That means,

$\frac{0.760}{[M+3(35.5)]}=\frac{1.610}{[M+3(126.9)]}$

$\frac{0.760}{[M+106.5]}=\frac{1.610}{[M+380.7]}$

$M=138.667g/mol$

From this we conclude that the element (X) is lanthanum (La) that has molecular weight, 138.667 g/mol.

Hence, the chemical symbol for this element is, (La)

6 0

4 years ago

Aspartame (c14h18n2o5) is a solid used as an artificial sweetener. its combustion produces carbon dioxide gas, liquid water, and

Law Incorporation [45]

Aspartame (C₁₄H₁₈N₂O₅) is a solid used as an artificial sweetener. its combustion produces carbon dioxide gas, liquid water, and nitrogen gas

C₁₄H₁₈N₂O₅ + 16O₂-----> 14CO₂ + 9H₂O + N₂.

As it can be seen from the equation, that the coefficient of nitrogen gas in the balanced equation for the reaction is 1.

So the answer here is 1 only that is coefficient of nitrogen gas in the balanced equation for the reaction is 1.

5 0

4 years ago

Please help with this answer

Igoryamba

Answer:

The answer is wave B, wave A

Explanation:

The closer the waves the higher the pitch. The higher the waves the louder it is.

4 0

3 years ago

Read 2 more answers

Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. If 70.8 g of c

Rus_ich [418]

Answer:

1.18 moles of CS₂ are produced by the reaction.

Explanation:

We present the reaction:

5C + 2SO₂ → CS₂ + 4CO

5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.

As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles

8 0

3 years ago