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loris [4]
3 years ago
6

True or false: Atoms and mass are conserved in nature True False

Chemistry
1 answer:
katovenus [111]3 years ago
5 0

Answer:

It’s true

Explanation:

If we account for all reactants and products in a chemical reaction, the total mass will be the same at any point in time in any closed system. ... The Law of Conservation of Mass holds true because naturally occurring elements are very stable at the conditions found on the surface of the Earth.

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Match the characteristics and elements to their group.
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Answer:

Kr is a Noble Gas. Na is an alkali metal. F is halogen.

Group 17 is halogens. Inert is Noble Gases. Odourless and colourless is Noble Gases. Alkali metals do not occur freely in nature. Alkali metals are malleable

Explanation:

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Zn(CrO4)2<br> What is the name of the compound
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Zinc chromate

Explanation:

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What are two ways that nonmetallic minerals can be used?
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A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters. The density of this substance BLANK) ( grams/mill
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A bottle containing air is initially at a temperature of 33 degrees C and a pressure of 0.81 atm. After being placed in the free
Georgia [21]

Answer:

The final pressure is 0.725 atm.

Explanation:

Gay Lussac's Law establishes the relationship between pressure and temperature of a gas when the volume is constant. This law says that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, pressure and temperature are directly proportional quantities.

Mathematically, Gay-Lussac's law states that, when a gas undergoes a constant volume transformation, the quotient of the pressure exerted by the gas temperature remains constant:

\frac{P}{T}  =k

When analyzing an initial state 1 and a final state 2, the following is satisfied:

\frac{P1}{T1}  =\frac{P2}{T2}

In this case:

  • P1= 0.81 atm
  • T1= 33 C= 306 K
  • P2= ?
  • T2= 1 C= 274 K

Replacing:

\frac{0.81 atm}{306 K}  =\frac{P2}{274 K}

Solving:

P2=274 K*\frac{0.81 atm}{306 K}

P2= 0.725 atm

<u><em>The final pressure is 0.725 atm.</em></u>

4 0
3 years ago
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