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2 years ago

The saints have 20 points and the Eagles have 14 points What is the difference between the two?

Mathematics

2 answers:

liraira [26]2 years ago

8 0

Answer:

The difference is 6 points.

Step-by-step explanation:

Given,

The saints having points = 20,

While, the eagles having points = 14,

Since, 20 > 14,

$\implies\text{ Saint's point}> \text{Eagle's point}$ ,

Thus, the difference in their points = Saint's point - Eagle's point

$= 20 - 14$

$= 6\text{ points}$

OverLord2011 [107]2 years ago

3 0

Answer:

The difference between the two is, 6

Step-by-step explanation:

Difference of any two real numbers states that:

if x and y are real number, then

$|x-y| = |y-x|$

As per the given statement:

the saints have 20 points

the eagles have 14 points.

To find the difference between the two is;

By definition, we have;

$|20-14| = |14-20| = 6$

Therefore, the difference between the two is, 6

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Whats the difference between 4x and x4

NNADVOKAT [17]

4x is substitution and x4 is to multiply. hope that helped

4 0

3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

3(2+4x)=−7x2 please give step by step and end with improper fraction as answer

SVETLANKA909090 [29]

Answer:

$\frac{-5}{3}$

Step-by-step explanation:

3(2 + 4x) = -7 x 2 Distribute the 3

6 + 12x = -14 Subtract 6 from both sides of the equation

12x = -20 Divide both sides by 12

x = $\frac{-20}{12}$ Divide the top and the bottom of the fraction by 4

x = $\frac{-5}{3}$

6 0

1 year ago

Read 2 more answers

Reyansh filled a 500-milliliter container with clean water. He then drank 35 percent of the water in the container. How many mil

galben [10]

He then drank 35 percent of the water in the container
so 65% left in in the container

0.65 x 500 = 325 milliliter

answer
325 milliliter of water left in the container

3 0

2 years ago

Read 2 more answers

HELP ME please! Plot the approximate location of V6 on the number line

deff fn [24]

Answer:

Sqrt of 6 = 2.449… round = 2.4 is less than 2.5

Step-by-step explanation:

4 0

2 years ago